Equation Solving: sin(x) - cos(2x) = 0

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SUMMARY

The discussion centers on solving the equation sin(x) - cos(2x) = 0, which is critical for finding the critical numbers of the function f(x) = 2cos(x) + sin(2x). Participants highlight the use of the identity cos(2x) = 1 - 2sin²(x) to simplify the equation. This substitution allows for a more straightforward approach to solving for x. The focus is on leveraging trigonometric identities to facilitate the solution process.

PREREQUISITES
  • Understanding of trigonometric identities, specifically cos(2x) = 1 - 2sin²(x)
  • Knowledge of calculus concepts, particularly critical numbers and derivatives
  • Familiarity with solving trigonometric equations
  • Basic skills in algebraic manipulation of equations
NEXT STEPS
  • Study the derivation and application of trigonometric identities
  • Learn techniques for finding critical points in calculus
  • Explore methods for solving trigonometric equations systematically
  • Investigate the implications of critical numbers on function behavior
USEFUL FOR

Students in calculus, mathematics educators, and anyone interested in solving trigonometric equations and understanding critical points in functions.

reddawg
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Homework Statement



0 = sin(x) - cos(2x)

Original problem asks to find the critical numbers of f(x) = 2cos(x) + sin(2x) . . . above is its derivative simplified and what I need to solve.
 
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reddawg said:

Homework Statement



0 = sin(x) - cos(2x)

Original problem asks to find the critical numbers of f(x) = 2cos(x) + sin(2x) . . . above is its derivative simplified and what I need to solve.

Have you ever seen cos2x in any formula?
 
Yes...

cos2x=1-2sin^2(x)

I can use that to my advantage I realizes...
 

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