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Equations for Accelerated Motion Problem

  1. Oct 20, 2013 #1
    1. The problem statement, all variables and given/known data

    Starting from rest, a car accelerates for 8 seconds with a constat acceleration. During this time it travels 121 meters. Find its velocity at the end of the 8 seconds.

    2. Relevant equations
    a=(2x)t^2
    Vavg=(Vinital+Vfinal)/2


    3. The attempt at a solution
    First, I found the average velocity by deviding 121 by 8 to get 15.125.

    Second, (with instruction from my physics teacher), I found the acceleration.
    a=(2x)*8^2
    a=(2*121)/64
    242/64=3.78
    a=3.78 m/s


    Then, knowing the acceleration, I found the final velocity.

    Vavg=(0+Vfinal)/2
    15.125=(Vfinal)/2
    15.125*2=30.25 m/s
    So, Vfinal should be 30.25 m/s, correct? I'm fairly sure of my answer, but I like to check before I turn it in.


    Thanks in advance for a reply!:smile:
     
  2. jcsd
  3. Oct 21, 2013 #2
    seems good to me!!!......Answer is right.
     
  4. Oct 21, 2013 #3
    Thank you! You are so helpful.
     
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