(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Given the circle (x+1)^2 + (y-3)^2 = 25, determine the equations of the tangents to the circle with the slope -3/4.

2. Relevant equations

y = mx + b

3. The attempt at a solution

I thought that if I could find the equation of the line that passed through the center of the circle and had a slope perpendicular to -3/4 (4/3) I could then use the equation to find points on the circle which a tangent with a slope -3/4 touched and solve from there. However once I began doing this I started getting a bizarre number and stopped. I have no problem forming the equation of a tangent when given a point on the circle, but I can't figure out how to solve the question when only given the slope. Any help would be appreciated.

The textbook gives the answers as: 3x + 4y = 34, 3x + 4y = -16

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# Equations of a line tangent to a circle

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