Equilibrium at Constant Velocity

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SUMMARY

The problem involves three forces acting on a moving object, with two known forces: 80.0 N directed north and 60.0 N directed west. To maintain constant velocity, the third force must counterbalance the resultant of these two forces. The resultant force can be calculated using Pythagorean theorem and basic trigonometry, yielding a magnitude of 100 N directed southwest. The third force must therefore have a magnitude of 100 N directed in the opposite direction to maintain equilibrium.

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  • Proficiency in using Pythagorean theorem
  • Familiarity with trigonometric functions for angle calculations
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Tater
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Hi there. This problem is very basic but I really cannot figure out how to solve it. I'm missing something but I have no clue what it is.

Homework Statement


Three forces act on a moving object. One force has a magnitude of 80.0 N and is directed due north. Another has a magnitude of 60.0 N and is directed due west. What must be the magnitude and direction of the third force, such that the object continues to move with a constant velocity?

Homework Equations


Force X Y
F1 F1Cos90 F1Sin90
F2 -F2Cos90 F2Sin90
W 0 -W=-mg

The Attempt at a Solution


F1Cos90-F2Cos90+0=0 (Then divide by Cos90)
F1=F2=>F

FSin90+FSin90=mg
2FSin90=mg
F=mg/2(Sin90)
F=mg/2(1)
F=mg/2
I would be very thankful if someone could please tell me what I'm doing wrong and what I should be doing so that I may learn from this question.
 
Last edited:
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There is no mention of gravity in this problem, so do not try to include it in your solution. Calculate the resultant of the two given forces (magnitude and direction)..one force is along the y-axis and the other along the x axis...use pythagorus and basic trig to calculate it. Then what must the third force be to keep the object moving at constant velocity (HINT: Use Newton 1).
 

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