Equilibrium Constant for Calcium Carbonate Reaction at 500 C

Click For Summary
SUMMARY

The equilibrium constant for the reaction of Calcium Carbonate (CaCO3) decomposing into Calcium Oxide (CaO) and Carbon Dioxide (CO2) at 500°C is determined using the equilibrium pressure of CO2, which is 1.2 x 10^-3 atm. The equilibrium expression for this reaction is based on the partial pressure of the gaseous product, CO2. The relationship between pressure and concentration is established through the ideal gas law, PV=nRT, allowing for the calculation of molarity from pressure. Therefore, the equilibrium constant (K) can be accurately calculated using the pressure of CO2 at the specified temperature.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with the ideal gas law (PV=nRT)
  • Knowledge of equilibrium constant expressions
  • Basic principles of thermodynamics related to gas behavior
NEXT STEPS
  • Calculate the equilibrium constant (K) for the reaction at 500°C using the provided pressure of CO2.
  • Explore the relationship between pressure and concentration in gaseous reactions.
  • Study the effects of temperature on equilibrium constants for various reactions.
  • Investigate the implications of Le Chatelier's principle on the equilibrium of gas reactions.
USEFUL FOR

Chemistry students, chemical engineers, and researchers interested in thermodynamics and chemical equilibrium analysis.

Hypercase
Messages
62
Reaction score
0
Calcium Carbonate is heated in a closed vessel, and an equilibrium is reached.

CaCO3 (s) <=> CaO(s) + CO2 (g)
At 500 C the equilibrium pressure of carbon dioxide is 1.2*10^-3 atm and at 1000 C it is 3.87 atm.
what is the equilibrium constant for this reaction at 500 C? :confused:
 
Physics news on Phys.org
Try posting your questions in the chemistry subforum here at PF (I don't have the time to help you at the moment).
 
I'm not really good at chemistry but isn't it 1.2*10^-3? The only gas around is CO2 so writing the equlibrium formula gives CO2's pressure. This probably isn't right but how to do it?
 
The equilibrium formula refers to concentration not pressure of a liquid. Is it the same for a gas? or is the pressure used in the case of a gas?
 
I think I got it right now. Since PV=nRT, P=MRT. Thus, M=P/RT. I think you can do the rest.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
9K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K