Equilibrium Constant: H2+O2->H2O

[Entanglement]

H2+1/2 O2 ---------> H20

If the equation is multiplied by 2
Will the equilibrium constant change or remain constant ?

 

[Useful nucleus]

The square of a constant is still a constant.

 

[Entanglement]

The square of a constant is still a constant.

Sorry, I don't understand, can you clarify what you mean, thanks.

 

[Borek]

Equilibrium constant will change, but as it will describe different reaction equation, you will find when the correct combination of the equation and constant is used, results of equilibrium calculations are identical.

 

[Useful nucleus]

Sorry, I don't understand, can you clarify what you mean, thanks.

Suppose you calculate a constant for the above reaction and its value is K. If you multiply the equation by 2, then the new constant will be K² .

But this should not matter for any intensive or molar quantity.