Equilibrium Physics Help: Calculating Kp for a Hydrogen Iodide Reaction

[terainfizik]

Homework Statement

In an experiment , b mole of hydrogen iodide were put into a sealed vessel under pressure p . At equilibrium, x mole of the hydrogen iodide had dissociated , the reaction being represented by the following equation ,
Express in terms of b and x of Kp .

Homework Equations

2HI(g) <---> H2(g) + I2(g)

The Attempt at a Solution

Here is my solution :
Reactant:
Before experiment : b mole of hydrogen iodide under pressure , p
At equilibrium : x mole of hydrogen iodide
P(pressure) for hydrogen iodide : [(p/b).(x)]^2

Products:
Before experiment : unknown
At equilibrium : I conclude that mole ratio of total products is the ( b-x )
mol . Therefore ,
P(pressure) for gas hyrogen and gas iodine : [(b-x).(p/b)]^2


Answer:
Kp = ([(b-x).(p/b)]^2 ) / ([(p/b).(x)]^2)
= (b^2) / (b-x)^2


If I am wrong , please guide me .

 

[terainfizik]

Nobody guide me here ?

 

[terainfizik]

Somebody help me please .

 

[Gokul43201]

Pay careful attention to the question: "x mole of the hydrogen iodide had dissociated ".