Equilibrium: Solving the Homework Puzzle

Click For Summary
SUMMARY

The discussion centers on solving a physics homework problem related to equilibrium forces in a system of pipes. The user calculated the forces acting on two pipes, determining that the force exerted by the second pipe and the normal force at point C is 1387.344N. For the bottom pipe, the normal forces at points B and A were calculated to be 4162.031N and 3924N, respectively. The user questions the accuracy of their results compared to the answer provided in the linked resource.

PREREQUISITES
  • Understanding of equilibrium equations in physics, specifically Fx = Fcos(theta) and Fy = Fsin(theta).
  • Familiarity with normal forces in static systems.
  • Basic knowledge of vector resolution in force analysis.
  • Ability to isolate components of a system for analysis.
NEXT STEPS
  • Review the principles of static equilibrium in mechanical systems.
  • Study vector resolution techniques for force analysis.
  • Examine examples of similar problems involving multiple forces and normal forces.
  • Learn about common pitfalls in equilibrium calculations and how to avoid them.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and equilibrium, as well as educators seeking to clarify concepts related to force analysis in static systems.

depre87
Messages
8
Reaction score
0

Homework Statement


http://answers.yahoo.com/question/index?qid=20090812013110AAcrnFs


Homework Equations


Equilibrium - Fx = Fcos(theta), Fy = Fsin(theta)



The Attempt at a Solution


I've got the answer however it's different to the one posted the link above - isolated the top pipe and used equilibrium for the forces which were - normal force at C the weight W of the pipe and the force F exerted by the 2nd pipe. By doing this I found that F and C is 1387.344N. Then isolated the bottom pipe - forces present were - normal force at B and A, W and F exerted by 1st pipe. Did equilibrium and ended up with normal force at B = 4162.031N and normal force at A to be 3924N.
Did I do something wrong or is there an issue with the answer on the link?
 
Physics news on Phys.org
depre87 said:

Homework Statement


http://answers.yahoo.com/question/index?qid=20090812013110AAcrnFs


Homework Equations


Equilibrium - Fx = Fcos(theta), Fy = Fsin(theta)



The Attempt at a Solution


I've got the answer however it's different to the one posted the link above - isolated the top pipe and used equilibrium for the forces which were - normal force at C the weight W of the pipe and the force F exerted by the 2nd pipe. By doing this I found that F and C is 1387.344N. Then isolated the bottom pipe - forces present were - normal force at B and A, W and F exerted by 1st pipe. Did equilibrium and ended up with normal force at B = 4162.031N and normal force at A to be 3924N.
Did I do something wrong or is there an issue with the answer on the link?

Not a very successful link ?
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
8
Views
7K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
4
Views
5K
  • · Replies 16 ·
Replies
16
Views
2K