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## Homework Statement

The equation x^2+3x-0.45=0 has two solutions x1=0.14 and x2=-3.14, these are supposed to be the locations at which the electric charge is in equilibrium with two other charges, should I use the first derivative to see at which location the charge will be stable?

## Homework Equations

x^2+3x-0.45=0

## The Attempt at a Solution

f’=2x+3, f’(x1)>0 so the charge is stable, is my reasoning correct?