Equilibrium, Torque and Tension

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SUMMARY

The discussion centers on calculating the tension in a rope supporting two uniform rafters, each weighing 150 N, with a 500 N load at their apex. The participant struggles with incorporating the unknown tension force (Ft) into the equilibrium equations, specifically the torque equations. The correct approach involves applying the torque equilibrium condition, ensuring that the sum of clockwise and counterclockwise torques equals zero. The participant is advised to write out the equilibrium equations for both rafters, including the hinge force at the upper end, to accurately determine the tension in the rope.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with torque calculations and the equation τ=lα
  • Knowledge of forces in two dimensions (Fx + Fy + Fz = 0)
  • Basic concepts of truss structures and load distribution
NEXT STEPS
  • Study the derivation of torque equations in static systems
  • Learn how to apply the method of joints in truss analysis
  • Explore the concept of reaction forces at supports in static equilibrium
  • Practice solving similar problems involving multiple forces and torques
USEFUL FOR

Students studying physics or engineering, particularly those focusing on statics, mechanics, and structural analysis. This discussion is beneficial for anyone looking to understand the principles of equilibrium in truss systems.

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Homework Statement



A truss is made by hinging two uniform, 150-N rafters as depicted in the diagram below. They rest on an essentially frictionless floor and are held together by a horizontal tie rope. A 500-N load is held at their apex. Find the tension in the rope.

nlc4yf.jpg


Homework Equations



τ=lα; Sum (torque CW) + Sum (torque CCW) = 0; Fx+Fy+Fz=0

The Attempt at a Solution



I think I am most confused at how to include the unknown tension force Ft into building the equilibrium equation. I assume the rope exert a tension force on the left rafter (Ft1) and another one at the right rafter (Ft2, equal magnitude as Ft1 but dir reversed). After I include Ft1 and Ft2 into the torque equation (I took the left rafter contact point with the ground as the axis of rotation), almost all the terms canceled out and it left me with something like Ft * something = 0, which, in turn, suggesting my result will be 0, which, is not correct, obviously.

Can someone explains to me what did I do wrong? And, how to solve this problem correctly? Thank you.
 

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Write out the equilibrium quations separately to both rafters, including the force from the hinge at the upper end.

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