Equipotential Surfaces physics problems

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SUMMARY

The discussion focuses on solving physics problems related to equipotential surfaces and charge conservation in spherical conductors. The user identifies two spheres, with charge Q1 on the inner sphere and Q2 on the outer sphere, applying Gauss's law to derive Q1=+2Q and Q2=-2Q. The user correctly notes that the total charge on the conductor is -5Q and emphasizes that charges will redistribute to minimize potential energy while adhering to Gauss's law. The conclusion highlights the importance of understanding the behavior of charges in conductive materials.

PREREQUISITES
  • Understanding of Gauss's Law
  • Knowledge of charge conservation principles
  • Familiarity with equipotential surfaces
  • Basic concepts of electrostatics and conductors
NEXT STEPS
  • Study Gauss's Law applications in electrostatics
  • Explore the concept of equipotential surfaces in depth
  • Investigate charge distribution in conductors
  • Learn about potential energy minimization in electrostatic systems
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Students and educators in physics, particularly those focusing on electrostatics, charge distribution, and equipotential surfaces in conductive materials.

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Homework Statement


attachment.php?attachmentid=60700&stc=1&d=1375709755.png

Homework Equations


- Charge conservation
- Equipotential surfaces

The Attempt at a Solution


Let Q1 be the amount of charge on the inner sphere with radius c, and Q2 be the amount of charge on the outer sphere with radius b.
Using Gauss's law, I figured out that Q1=+2Q and Q2=-2Q
1/ Charge conservation: Q1+Q2=0 (1)
2/ Equipotential surfaces: \frac{kQ_{1}}{c}=\frac{kQ_{2}}{b}(2)
(1),(2)=>Q1=Q2=0
Since my understanding on equipotential surfaces is not very good, please correct me if I am wrong, thank you!
 

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Do you even need calculation? When they are joined by a wire the two spheres can be said to be parts of the same conductor. We know that the total charge on the conductor is -5Q. There are many ways to distribute this charge but they will move so as to minimise the potential energy of the system and obey Gauss law. What will happen? (This situation is same as that of a solid spherical conductor with a cavity).
 

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