Equivalence between power sets

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SUMMARY

The discussion centers on proving the identity P(A) ∩ P(B) = P(A ∩ B) using the equivalence established in part a, which states that if X ⊆ Y and X ⊆ Z, then X ⊆ Y ∩ Z. The user attempts to prove two propositions: Proposition 1 shows that P(A ∩ B) ⊆ P(A) ∩ P(B), while Proposition 2 demonstrates that P(A) ∩ P(B) ⊆ P(A ∩ B). The user expresses confusion about the necessity of certain logical steps and the clarity of their proof structure.

PREREQUISITES
  • Understanding of set theory concepts, including subsets and intersections.
  • Familiarity with power sets and their properties.
  • Knowledge of logical reasoning and proof techniques in mathematics.
  • Ability to translate mathematical statements into formal proofs.
NEXT STEPS
  • Study the properties of power sets in detail, focusing on P(A ∩ B).
  • Learn about logical proof techniques, specifically direct proof and proof by contradiction.
  • Review examples of set theory proofs to understand common structures and strategies.
  • Practice translating informal mathematical reasoning into formal proofs.
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Students of mathematics, particularly those studying set theory and proof techniques, as well as educators seeking to clarify concepts related to power sets and logical reasoning.

dndod1
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Homework Statement


Part a: Show that X \subseteq Y and X \subseteq Z if and only if X\subseteq Y \cap Z, for sets X,Y,Z. I have done this.

Part b: Use the equivalence from part a to establish the identity P(A) \cap P(B)= P(A \cap B), where P is the power set.


Homework Equations


The proof from part a


The Attempt at a Solution


This is as far as I can get and I'm not convinced that I am headed in the right direction.

Let P(A)= Y Let P(B)=Z Let P(A \cap B) = X
Because we need to show =, we must show 2 propositions.
Proposition 1:
That P(A \cap B) \subseteq P(A) \cap P(B)


Proposition 2:
That P(A) \cap P(B) \subseteq P(A intesection B)


Proposition 1: translates directly into what we had in part a.
X \subseteq (Y \cap Z) So no further proof needed?

Proposition 2: translates into (Y \cap Z) \subseteq X
Let x be an element of X
As (Y \cap Z) \subseteq X, x \in (Y \cap Z) from part a
As x \in (Y \cap Z), x \in Y and x \inZ

Here is the point where I am really lost! Did I need the "x \in X" part at all?


Any assistance to get me on the right track would be greatly appreciated.
Many thanks!
 
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dndod1 said:
Proposition 1: translates directly into what we had in part a.
X \subseteq (Y \cap Z) So no further proof needed?

Proposition 2: translates into (Y \cap Z) \subseteq X
Let x be an element of X
As (Y \cap Z) \subseteq X, x \in (Y \cap Z) from part a
As x \in (Y \cap Z), x \in Y and x \inZ

Here is the point where I am really lost! Did I need the "x \in X" part at all?

I don't understand how you are getting things "translating" into another thing, and you should be showing all your working clearly as well. And don't rename the sets because it doesn't save that much time and hides what you are actually dealing with.

The easiest way to to showing M is a subset of N is by saying "Let x be in M" then use logical steps to show "Thus x is in N".

For Proposition 1) start with "Let x be an element of the power set of (A intersection B). By the definition of a power set, x is a subset of (A intersection B). By part a) ..."

Then do similar for the next one.
 
Thanks for that. I shall give it another go. If I don't relate the sets in part b to what I showed in part a, am I not ignoring the part of the question that says "Use the equivalence from part a"?
 
Well, whether you explicitly state you used it or not, you will have to to complete the proof anyway, and since you have to explain all your reasoning, when you do use it you'll have to mention that you proved that fact in part a).
 

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