MHB Equivalences and Partitions and Properties of binary relations

Click For Summary
The discussion centers on a request for assistance with questions about equivalences, partitions, and properties of binary relations. The response emphasizes the importance of adhering to forum rules, particularly regarding the number of questions allowed per thread. Rule 8 specifically limits users to two questions, while the original post included twenty. Participants are encouraged to familiarize themselves with the forum's guidelines to ensure productive interactions. Following the rules will enhance the likelihood of receiving help effectively.
sadsadsadsa
Messages
15
Reaction score
0
If someone could explain some of the steps needed to work out these 2 questions it would be much appreciated!

View attachment 4276View attachment 4277
 

Attachments

  • 8788.compressed (1).1-10.pdf
    8788.compressed (1).1-10.pdf
    196.8 KB · Views: 104
  • 8788.compressed (1).10-20.pdf
    8788.compressed (1).10-20.pdf
    203.2 KB · Views: 118
  • 8788.compressed (1).10-20-page-004.jpg
    8788.compressed (1).10-20-page-004.jpg
    32.8 KB · Views: 82
  • 8788.compressed (1).10-20-page-007.jpg
    8788.compressed (1).10-20-page-007.jpg
    38.8 KB · Views: 82
Last edited:
Physics news on Phys.org
Hello, sadsadsadsa!

We would be glad to help, but you should study the http://mathhelpboards.com/rules/ first. On the rules page, click on the Expand button in the top-left corner. In particular, read rules 8, 11 and 6. Thus, rule 8 asks not to ask more than two questions in a thread, while you posted 20 questions in total.
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

Similar threads

Replies
3
Views
2K
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K