yungman
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I want to model a coil circuit with induced EMF. I want to verify that my model is correct in a circuit. That the voltage developed across the load is calculated correctly. From the equivalent circuit, you can see the current depend on the jX_L and it acts as a low pass filter in the complete circuit loop because the value increase and cause less voltage develop across the Load.
Let coil:
Z_L=R_L+jX_L
Maxwell eq. For EMF induction:
\nabla\times \vec E =-\frac {\partial \vec B}{\partial t}\;\Rightarrow\; \int_S \nabla \times \vec E\;\cdot\;d\vec S = \int_C \vec E\cdot d \vec l = -\frac{\partial}{\partial t}\left(\int_S \vec B \cdot d\vec S\right)=-\frac{\partial \Phi}{\partial t}
Where \Phi\; is the magnetic flux. Therefore induced EMF:
V_{IND}= \int_S \nabla \times \vec E\;\cdot\;d\vec S = \int_C \vec E\cdot d \vec l = -\frac{\partial}{\partial t}\left(\int_S \vec B \cdot d\vec S\right)=-\frac{\partial \Phi}{\partial t}
To put the whole thing together, using the coil to drive the load, the total equivalent circuit is shown with the \;V_{IND}\; modeled as an ideal voltage source:
146972[/ATTACH]"]
where I use Z_L=R_L+jX_L and the current in the loop is:
I= \frac {V_{IND}}{R_L+jX_L+R_{LOAD}}\;\hbox { and }\; V_{LOAD}=I\;R_{LOAD}
I updated that the load is a pure resistance, not reactance, or else it can really get dicey!
Thanks
Alan
Let coil:
Z_L=R_L+jX_L
Maxwell eq. For EMF induction:
\nabla\times \vec E =-\frac {\partial \vec B}{\partial t}\;\Rightarrow\; \int_S \nabla \times \vec E\;\cdot\;d\vec S = \int_C \vec E\cdot d \vec l = -\frac{\partial}{\partial t}\left(\int_S \vec B \cdot d\vec S\right)=-\frac{\partial \Phi}{\partial t}
Where \Phi\; is the magnetic flux. Therefore induced EMF:
V_{IND}= \int_S \nabla \times \vec E\;\cdot\;d\vec S = \int_C \vec E\cdot d \vec l = -\frac{\partial}{\partial t}\left(\int_S \vec B \cdot d\vec S\right)=-\frac{\partial \Phi}{\partial t}
To put the whole thing together, using the coil to drive the load, the total equivalent circuit is shown with the \;V_{IND}\; modeled as an ideal voltage source:
146972[/ATTACH]"]
where I use Z_L=R_L+jX_L and the current in the loop is:
I= \frac {V_{IND}}{R_L+jX_L+R_{LOAD}}\;\hbox { and }\; V_{LOAD}=I\;R_{LOAD}
I updated that the load is a pure resistance, not reactance, or else it can really get dicey!
Thanks
Alan
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