Equivalent definitions of random variable

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mnb96
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Hello,

According to the Wikipedia article on random variables:
"Any random variable can be described by its cumulative distribution function, which describes the probability that the random variable will be less than or equal to a certain value."
If the above statement is true, then, instead of defining a (real) random variable as a function from a sample space of some probability space to the reals, could we equivalently define it as a subset of ℝ associated with a CDF?
 
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mnb96 said:

In its current state, that article has some self-contradictions. The abstract definition it gives for random variable looks correct. The statements it makes about cumulative distributions are misleading.

Consider the following situation. We have two questionnaires. Questionnaire A is designed to rate a persons interest in applied mathematics "on a scale" from 0 to 10. Questionnaire B is designed to rate a person's interest in basketball on a scale from 0 to 10.

A realization of Random variable X is defined as "Pick a student at your school at random and administer questionnaire A. Let X be the student's score on the questionnaire. A realization of Random variable Y is defined as "Pick a student at you school at random and administer questionnaire B. Let Y be the student's score on questionnaire B.

It is possible that random variable X and random variable Y might have the same distribution and same cumulative distribution. But the two random variables are not the same random variable because they are not defined on the same probability space. X is defined on a space of events having to do with questionnaire A while Y is defined on a space of events having to do with questionnaire B.
 
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Hey mnb96.

A graduate course in probability will make this definition more precise.

The idea is that you have a sigma algebra, a Borel space and you mix the two up to make the idea of a probability space [with its events and actual probabilities] consistent with what a probability space actually is.
 
OK.
Thank you all. I think all the answers I received were pretty clear.