Equivalent Resistor Calculation for Series and Parallel Circuits

[ongxom]

Homework Statement

Calculate equivalent resistor

The Attempt at a Solution

R_eq=(10 series 5)//(10)//(3)//(2)//(9 series 40) series 8//(4)

I am not sure in the bolded text, is 9Ω connected serially with 40Ω.

 

[gneill]

Nope. Redraw your circuit after performing the "(10 series 5)//(10)//(3)//(2)" operations.

 

[Simon Bridge]

Do it yourself and see.

 

[TimeToShine]

As said above, redraw the circuit. You have the equivalent resistance of the unbolded text correct. redraw the circuit and you should see it is similar to what you have already done.

 

[ongxom]

First : [(10 series 5)//(10)//(3)//(2)] series 9 = 10Ω
Redraw the circuit

Req = (40//10) series 4 series 8 = 20Ω

 

[gneill]

Yup. Looks good.