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Series/Parallel Resistor Circuits (Diagonal Resistor)

  1. Jul 28, 2015 #1
    1. The problem statement, all variables and given/known data
    http://i.gyazo.com/c6b73ca3a53b7d36bce59a0aa5009d27.png

    2. Relevant equations
    Kirchhoff's Current and Voltage Laws, Resistors in parallel and in Series.

    3. The attempt at a solution
    The main thing confusing me is the diagonal 6 Ohms, not too sure what it is parallel too and how to add them, however the answer i did achieve was adding the 10, 6 and 3 in parallel and finally adding the 8 which gives an answer of 9.6 recurring Ohms, however within my lecture, a person answered the problem as 5 ohms and the lecturer said he was correct, this is mainly just confusion on my part.
     
  2. jcsd
  3. Jul 28, 2015 #2

    SteamKing

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    For simple circuits such as this one, it helps to isolate a couple of resistors at a time, rather than trying to figure out how all of the resistors connect with one another at once.

    For this circuit, first look at R3 and R4. How are these two resistors connected with respect to one another?

    It also helps to redraw the circuit, keeping in mind to preserve the connections of the resistors with one another, as you progress.
     
  4. Jul 28, 2015 #3
    Thanks a lot, just found the answer to be 5,

    what I did was configure the circuit like so http://i.gyazo.com/6d2a8e8d117cd4be1ea9d53fde71e8fb.png

    calculate the resisatnce in parallel to reduce the circuit basically to http://i.gyazo.com/e8a352411f710659b0df79bb98191096.png

    which is also the same as http://i.gyazo.com/d27b9e7cc22cf9c63e836dcfa03d8ebe.png

    which equals a total of 5 ohms, was this deduction the correct way to approach?
     
  5. Jul 28, 2015 #4

    SteamKing

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