Equivalent torque of hollow shaft

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SUMMARY

The discussion focuses on calculating the equivalent dimensions of a hollow shaft that can replace a solid circular shaft with a diameter of 200mm while transmitting the same torque under maximum shear stress conditions. The internal and external diameters of the hollow shaft are specified to be in a 4:5 ratio. The final dimensions of the hollow shaft are determined to be 23.84 cm for the external diameter and 19.07 cm for the internal diameter, resulting in a material reduction of 48.9% compared to the solid shaft.

PREREQUISITES
  • Understanding of torque transmission in mechanical systems
  • Familiarity with shear stress and its calculations
  • Knowledge of polar moment of inertia (J) and its significance
  • Basic principles of ratios and proportions in engineering design
NEXT STEPS
  • Study the derivation of the polar moment of inertia for hollow shafts
  • Explore the implications of shear stress in different materials
  • Learn about the design considerations for hollow versus solid shafts
  • Investigate the effects of material reduction on structural integrity and performance
USEFUL FOR

Mechanical engineers, students in engineering mechanics, and professionals involved in shaft design and material optimization will benefit from this discussion.

Deathfish
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Homework Statement



A solid circular shaft has a diameter of 200mm. What would be the dimension of a hollow
shaft which could replace it (i.e. transmit the same torque for the same maximum shear
stress), and what would be the percentage reduction in the material required? The internal
and external diameters of the hollow shaft are to be in the ratio of 4:5. (Ans: 23.84 cm,
19.07 cm; 48.9%)

Homework Equations



T/J = G(theta)/L = tao/R
J = pi(d)^4/32


The Attempt at a Solution



J = pi(0.2)^4/32 = 0.000157

pi(5d)^4/32 - pi(4d)^4/32 = 0.000157

d = 0.2m

5d = 1m (wrong)
 
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Deathfish said:
The internal and external diameters of the hollow shaft are to be in the ratio of 4:5. (Ans: 23.84 cm,
19.07 cm; 48.9%)

You are right in that you want Jsolid = Jhollow

But this statement means that d/D = 4/5 or d = 0.8D (d = internal, D= external)

And Jhollow = π/32 (D4-d4)
 

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