I Error on a weighing scale due to wrong size

Click For Summary
When weighing a rigid object that overhangs a scale's tray, the measurement error is generally minimal, often estimated at zero unless the object is unevenly distributed or tilting the pan. The shape of the object can affect the measurement; for example, rod-shaped items can be positioned to minimize overhang. Conducting tests by weighing items with and without overhang can help assess precision and identify any variations. It's recommended to repeat measurements multiple times for accuracy. Overall, experimenting with different placements and shapes can provide insights into potential errors in weighing.
cloa513
Messages
36
Reaction score
4
If you have say a 15 centimetre long piece of rigid plastic and the weighing scale's tray is only 10 centimetres, what is an estimate of the error that introduces in the measurement assuming the weight is still within normal parameters for the weighing scale. I was wondering what the approximate error in general for moderately rigid materials? It happens now and again at work.
 
Physics news on Phys.org
I would expect zero, unless the overhanging part is resting on something or the weight distribution is so uneven it's tilting the pan.

What shape are the things you weigh? Can you hold them vertical somehow so they are fully within the pan? For example, if they are rod-shaped they could be placed horizontally across the top of a cup and then nearly-vertically in it. Then you could compare the measured weights with and without an overhang as a test. Remember to repeat each measurement a few times (take everything off the scale and put it back on) to check your precision.
 
  • Like
Likes Lord Jestocost
Shape of things- plates.
 
Hard for you to test, then. The answer is still zero.
 
cloa513 said:
I was wondering what the approximate error in general for moderately rigid materials?
Experiment with a test item, offset and hanging over the pan in different directions. Then break it up and weigh it in the pan. How much variation do you see?
 
Thread 'Why higher speeds need more power if backward force is the same?'
Power = Force v Speed Power of my horse = 104kgx9.81m/s^2 x 0.732m/s = 1HP =746W Force/tension in rope stay the same if horse run at 0.73m/s or at 15m/s, so why then horse need to be more powerfull to pull at higher speed even if backward force at him(rope tension) stay the same? I understand that if I increase weight, it is hrader for horse to pull at higher speed because now is backward force increased, but don't understand why is harder to pull at higher speed if weight(backward force)...

Similar threads

  • · Replies 59 ·
2
Replies
59
Views
6K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
3
Views
3K