dionysian
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Error propagation
Calculate:
\frac{ - \frac{R_{2}}{R_{1}}}{1 + \frac{1}{A} + \frac{R_{2}}{A R_{1}}}
R_{1} = 10000 \pm 5 \%
R_{2} = 10000 \pm 5 \%
A = 1000
I try to follow the example of at the website http://www.rit.edu/~uphysics/uncertainties/Uncertaintiespart1.html and in there example
x = ( 2.0 \pm 0.2)
y = (3.0 \pm 0.6)
z = \frac{x}{y}
This is what they do in their example:
z = \frac{2.0}{3.0} = 0.6667
\Delta z = 0.3 (0.6667 ) = 0.2
z = (0.7 \pm 0.2)
Now what i don't really understand is where they get 0.3 from?
It seems that they just divide the uncertainty \frac{0.2}{0.6} = .33.
But, if i do this in my example i get \frac{500}{500} = 1. Then when i multiply this agianst \frac{10000}{10000} = 1 i get 100% error. Yikes!
I kind of feel embarrassed asking this because i should have learned this a long time ago in physics but it was one of those things i never really took the time to actually understand.
Homework Statement
Calculate:
\frac{ - \frac{R_{2}}{R_{1}}}{1 + \frac{1}{A} + \frac{R_{2}}{A R_{1}}}
Homework Equations
R_{1} = 10000 \pm 5 \%
R_{2} = 10000 \pm 5 \%
A = 1000
The Attempt at a Solution
I try to follow the example of at the website http://www.rit.edu/~uphysics/uncertainties/Uncertaintiespart1.html and in there example
x = ( 2.0 \pm 0.2)
y = (3.0 \pm 0.6)
z = \frac{x}{y}
This is what they do in their example:
z = \frac{2.0}{3.0} = 0.6667
\Delta z = 0.3 (0.6667 ) = 0.2
z = (0.7 \pm 0.2)
Now what i don't really understand is where they get 0.3 from?
It seems that they just divide the uncertainty \frac{0.2}{0.6} = .33.
But, if i do this in my example i get \frac{500}{500} = 1. Then when i multiply this agianst \frac{10000}{10000} = 1 i get 100% error. Yikes!
I kind of feel embarrassed asking this because i should have learned this a long time ago in physics but it was one of those things i never really took the time to actually understand.
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