Error Propagation: Calculating Uncertainty of a Ratio

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The discussion focuses on calculating the uncertainty of a ratio in error propagation, specifically for the equation involving resistances R1 and R2, and a constant A. The user is confused about how to derive the uncertainty in their calculation, referencing an example from a website that uses relative errors. They question the source of a specific value (0.3) used in the example, which is clarified as the sum of the relative errors of the variables involved. The conversation emphasizes the importance of understanding how to properly calculate and combine uncertainties in physics problems. Understanding these concepts is essential for accurate error propagation in measurements.
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Error propagation

Homework Statement


Calculate:

\frac{ - \frac{R_{2}}{R_{1}}}{1 + \frac{1}{A} + \frac{R_{2}}{A R_{1}}}

Homework Equations



R_{1} = 10000 \pm 5 \%
R_{2} = 10000 \pm 5 \%
A = 1000

The Attempt at a Solution



I try to follow the example of at the website http://www.rit.edu/~uphysics/uncertainties/Uncertaintiespart1.html and in there example
x = ( 2.0 \pm 0.2)
y = (3.0 \pm 0.6)
z = \frac{x}{y}

This is what they do in their example:
z = \frac{2.0}{3.0} = 0.6667
\Delta z = 0.3 (0.6667 ) = 0.2
z = (0.7 \pm 0.2)

Now what i don't really understand is where they get 0.3 from?
It seems that they just divide the uncertainty \frac{0.2}{0.6} = .33.

But, if i do this in my example i get \frac{500}{500} = 1. Then when i multiply this agianst \frac{10000}{10000} = 1 i get 100% error. Yikes!

I kind of feel embarrassed asking this because i should have learned this a long time ago in physics but it was one of those things i never really took the time to actually understand.
 
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Now what i don't really understand is where they get from?
It seems that they just divide the uncertainty
The 0.3 comes from the addition of the relative errors of x and y. Find equation 2a on that page.
 
Thank you sir
 
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