Consider a spherical asteroid with a radius of 5 km and a mass of 8.65x10^15 kg.(adsbygoogle = window.adsbygoogle || []).push({});

(a) What is the acceleration of gravity on the surface of this asteroid?

ANSWER: ___ m/s2

(b) Suppose the asteroid spins about an axis through its center, like the Earth, with an angular speed . What is the greatest value can have before loose rocks on the asteroid's equator begin to fly off the surface?

ANSWER: ___ rad/s

For (a) which I got right.... I used the equation g=(G*M)/R^2

g=(6.67e-11*8.65e15)/(5000^2)=.023078 m/s2

For (b) I used the equation Wf^2= Wi^2 + 2*a*d and i substituted the numbers in to get... Wf^2 = 0 + 2(.023037*2pi)(31415.9m*2pi) and I got it to be 95.45 rad/s and for some reason this is not right... am I even using the right equation or is there another equation i can use to get the answer such as maybe... F= (G*M*m)/R^2 ....

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# Escape Velocity of a spherical asteroid

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