Estimate the density of the water

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SUMMARY

The discussion focuses on estimating the density of water at a depth of 5.7 km in the sea, utilizing the bulk modulus of water, which is B=2.0 x 10^9 N/m². Participants emphasize the importance of calculating pressure changes at this depth and suggest using the equation B=dP/(d(rho)/rho) to derive the density. The final formula derived is ln(rho2/rho1)=exp((P2-P1)/B), which allows for the comparison of densities at the surface and at depth. The conversation highlights the significance of pressure changes in determining water density at great depths.

PREREQUISITES
  • Understanding of fluid mechanics concepts, particularly pressure and density.
  • Familiarity with the bulk modulus and its application in fluid dynamics.
  • Knowledge of calculus for manipulating and integrating equations.
  • Basic understanding of hydrostatic pressure equations, specifically P=(rho)gh.
NEXT STEPS
  • Study the derivation and application of the bulk modulus in fluid mechanics.
  • Learn how to calculate pressure changes in fluids at varying depths.
  • Explore the integration techniques for solving differential equations in physics.
  • Investigate the effects of temperature and salinity on water density at different ocean depths.
USEFUL FOR

Students studying fluid mechanics, physicists interested in hydrostatics, and anyone involved in marine science or oceanography.

kritzy
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Homework Statement


Estimate the density of the water 5.7 km deep in the sea. (bulk modulus for water is B=2.0 x 10^9 N/m^2) By what fraction does it differ from the density at the surface?

Homework Equations


P=(rho)gh=F/A=B(delta l/l)

The Attempt at a Solution


So I have several equations above. I wanted so solve for rho using the first equation but I don't know pressure. I tried the second equations but I don't know Force or area. I tried the last equation but I would need delta l and l so basically I'm stuck. Some advice would be much appreciated.
 
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kritzy said:
Estimate the density of the water 5.7 km deep in the sea. (bulk modulus for water is B=2.0 x 10^9 N/m^2) By what fraction does it differ from the density at the surface?

Homework Equations


P=(rho)gh=F/A=B(delta l/l)

The Attempt at a Solution


So I have several equations above. I wanted so solve for rho using the first equation but I don't know pressure. I tried the second equations but I don't know Force or area. I tried the last equation but I would need delta l and l so basically I'm stuck. Some advice would be much appreciated.

Well they do say estimate. So maybe try to work it out assuming that p doesn't change?

(Yes it changes, but does it change enough to matter? See what results you get and then decide.)
 
LowlyPion said:
Well they do say estimate. So maybe try to work it out assuming that p doesn't change?

(Yes it changes, but does it change enough to matter? See what results you get and then decide.)

I don't understand. I'm suppose to be solving for p at a certain density. How can it not change?
 
kritzy said:
I don't understand. I'm suppose to be solving for p at a certain density. How can it not change?

Have you calculated it using a uniform p as to the effect it will have on a bulk modulus of 2 * 109?
 
In 6 km, the change in pressure is significant.

Here's something to get you started:

Use the equation,

B=dP/(d(rho)/rho)

Manipulate and integrate,

integral of (d(rho)/rho) = integral of (dP/B)

That results in,

ln(rho2/rho1)=exp((P2-P1)/B)

Where you can say state 1 is the surface, and state 2 is the state at 5.7 km down.

You can then use the rho*g*h equation.
 

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