Estimate the radiation pressure

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SUMMARY

The discussion focuses on estimating the radiation pressure from a 100 W bulb at a distance of 0.08 m. The radiation pressure is calculated using the formula Prad = P / (SA * c), resulting in a value of 4.15 x 10^-6 Pa. Subsequently, the force exerted on a fingertip with an area of 0.0001 m² is determined to be 4.15 x 10^-10 N. The calculations assume a perfectly absorbing surface, although the fingertip's reflectivity is acknowledged as a factor that could influence the results.

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  • Understanding of radiation pressure and its formulas
  • Familiarity with the concept of intensity (I) and its relation to power (P)
  • Knowledge of the speed of light (c) and its calculation using μo and εo
  • Basic principles of force calculation using area and pressure
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  • Learn about the impact of reflectivity on radiation pressure calculations
  • Explore the concept of intensity in electromagnetic radiation
  • Investigate the effects of different surface materials on radiation pressure
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Students in physics, engineers working with optical systems, and anyone interested in the practical applications of radiation pressure in real-world scenarios.

ooohffff
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Homework Statement


a) Estimate the radiation pressure due to a 100 W bulb at a distance of .08 m from the center of the bulb.
b) Estimate the force exerted on your fingertip if you place it at this point. (Assume an area of .0001 m2 for the fingertip.)

Homework Equations


F=PradA

The Attempt at a Solution


a) I'm assuming the radiation is like a sphere. I'm a little confused on what radiation pressure formula to use in this situation. I have formulas for perfectly absorbing and perfectly reflecting?

Power = 100W
r = .08m
SA = 4πr2

b) I know that the Force = Pressure * Area of fingertip, so I would need to get a) right to get b)
 
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Would the equation be:

Prad = I / c ?

Plugging stuff in, this is what I get:

c = 1/√(μoεo)
I = P/ (SA)
Prad = P / ( (SA)*c ) = 100W/ (4π(.08)2*c) = 4.15*10-6 Pa

F= (4.15*10^-6 Pa) * (.0001 m2) = 4.15*10-10 N
 
ooohffff said:
I have formulas for perfectly absorbing and perfectly reflecting?
I would assume the absorbing case here. Please quote it.
 
ooohffff said:
Would the equation be:

Prad = I / c ?

Plugging stuff in, this is what I get:

c = 1/√(μoεo)
I = P/ (SA)
Prad = P / ( (SA)*c ) = 100W/ (4π(.08)2*c) = 4.15*10-6 Pa

F= (4.15*10^-6 Pa) * (.0001 m2) = 4.15*10-10 N
Looks right, except your fingertip will have some reflectivity.
 
haruspex said:
Looks right, except your fingertip will have some reflectivity.
Great thanks!
 

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