Estimate the radiation pressure

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Homework Help Overview

The discussion revolves around estimating the radiation pressure from a 100 W bulb at a distance of 0.08 m, along with calculating the force exerted on a fingertip placed at that distance. The subject area includes concepts of radiation pressure and the associated equations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand which radiation pressure formula is applicable, considering cases for perfectly absorbing and reflecting surfaces. Some participants propose using the intensity and speed of light to derive the radiation pressure.

Discussion Status

Participants are exploring different equations and approaches to calculate radiation pressure and force. There is some agreement on the use of specific formulas, but questions remain about the assumptions regarding the fingertip's reflectivity.

Contextual Notes

There is a mention of needing to clarify the appropriate formula for radiation pressure based on the absorbing or reflecting nature of the fingertip, which may affect the calculations.

ooohffff
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Homework Statement


a) Estimate the radiation pressure due to a 100 W bulb at a distance of .08 m from the center of the bulb.
b) Estimate the force exerted on your fingertip if you place it at this point. (Assume an area of .0001 m2 for the fingertip.)

Homework Equations


F=PradA

The Attempt at a Solution


a) I'm assuming the radiation is like a sphere. I'm a little confused on what radiation pressure formula to use in this situation. I have formulas for perfectly absorbing and perfectly reflecting?

Power = 100W
r = .08m
SA = 4πr2

b) I know that the Force = Pressure * Area of fingertip, so I would need to get a) right to get b)
 
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Would the equation be:

Prad = I / c ?

Plugging stuff in, this is what I get:

c = 1/√(μoεo)
I = P/ (SA)
Prad = P / ( (SA)*c ) = 100W/ (4π(.08)2*c) = 4.15*10-6 Pa

F= (4.15*10^-6 Pa) * (.0001 m2) = 4.15*10-10 N
 
ooohffff said:
I have formulas for perfectly absorbing and perfectly reflecting?
I would assume the absorbing case here. Please quote it.
 
ooohffff said:
Would the equation be:

Prad = I / c ?

Plugging stuff in, this is what I get:

c = 1/√(μoεo)
I = P/ (SA)
Prad = P / ( (SA)*c ) = 100W/ (4π(.08)2*c) = 4.15*10-6 Pa

F= (4.15*10^-6 Pa) * (.0001 m2) = 4.15*10-10 N
Looks right, except your fingertip will have some reflectivity.
 
haruspex said:
Looks right, except your fingertip will have some reflectivity.
Great thanks!
 

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