- #1
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How many terms of :
[tex] \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n^2} [/tex]
do you have to add to get an error < .01
Alright, I used the Alternating Series Estimation Theorem since the terms are decreasing and the terms approach 0.
So, by the theorem, .01 < = [tex] b_{n+1} [/tex] so
[tex] 1/(n+1)^2 = 1/100[/tex]
[tex] (n+1)^2 = 100 [/tex]
[tex] n+1 = 10[/tex]
So this means that in order to get this error, we have to add 9 terms right? The back of my book says 10 is the answer. Why is that?
[tex] \sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n^2} [/tex]
do you have to add to get an error < .01
Alright, I used the Alternating Series Estimation Theorem since the terms are decreasing and the terms approach 0.
So, by the theorem, .01 < = [tex] b_{n+1} [/tex] so
[tex] 1/(n+1)^2 = 1/100[/tex]
[tex] (n+1)^2 = 100 [/tex]
[tex] n+1 = 10[/tex]
So this means that in order to get this error, we have to add 9 terms right? The back of my book says 10 is the answer. Why is that?