Estimating water volume(so lost)

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A violent rainstorm dumps 1.7 cm of rain on a city 6.0 km wide and 8.0 km long in a 3.0 hr period. How many metric tons (1 ton = 103 kg) of water fell on the city? [1 cm3 of water has a mass of 1 g = 10-3 kg.]

any help would be greatly apreciated!
 
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1.7 cm =.017m=thickness
Width =6 km =6000m
length = 8 km =8000 m

t0al volume = .017 x 6000 x 8000
=81600 m^3
=81600 x (100 cm)3
=81600 x 1000000 cm^3
=81600000000 cm3


since 1cm^3 = 1 gram

81600000000 cm^3 = 81600000000 gm =81600000 kg

since 1 metric ton =103 kg
81600000 kg = 81600000 kg / 103 kg =

792233.09 metric ton

i hope this is right.
 
Ishu said:
1.7 cm =.017m=thickness
Width =6 km =6000m
length = 8 km =8000 m

t0al volume = .017 x 6000 x 8000
=81600 m^3
=81600 x (100 cm)3
=81600 x 1000000 cm^3
=81600000000 cm3


since 1cm^3 = 1 gram

81600000000 cm^3 = 81600000000 gm =81600000 kg

since 1 metric ton =103 kg
81600000 kg = 81600000 kg / 103 kg =

792233.09 metric ton

i hope this is right.

hey! thanks allot for the information
but i tried that answer and it said its wrong :frown:
oh well don't worry i'll keep on tryin because I'm at work here
and i have other online problems to do also though
 
Ishu said:
since 1 metric ton =103 kg
Not where I come from it isn't!:bugeye:

Is that some new "pi=3" Kansas law passed?
 
Hootenanny said:
1 metric ton or tonne is 1000 kg. I think you calcs may be correct now.


Yeah that why I was confised.. haha I was like " when did 103 kg became = 1 metric ton.." hahha
Since it was in the question I used it...
anyway the answer should be..

81600000 kg / 1000 kg = 81600 Ton