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Estimating water volume(so lost)

  1. Jan 31, 2006 #1
    A violent rainstorm dumps 1.7 cm of rain on a city 6.0 km wide and 8.0 km long in a 3.0 hr period. How many metric tons (1 ton = 103 kg) of water fell on the city? [1 cm3 of water has a mass of 1 g = 10-3 kg.]

    any help would be greatly apreciated!
     
  2. jcsd
  3. Jan 31, 2006 #2

    Hootenanny

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    Think about defining density.
     
  4. Jan 31, 2006 #3
    1.7 cm =.017m=thickness
    Width =6 km =6000m
    length = 8 km =8000 m

    t0al volume = .017 x 6000 x 8000
    =81600 m^3
    =81600 x (100 cm)3
    =81600 x 1000000 cm^3
    =81600000000 cm3


    since 1cm^3 = 1 gram

    81600000000 cm^3 = 81600000000 gm =81600000 kg

    since 1 metric ton =103 kg
    81600000 kg = 81600000 kg / 103 kg =

    792233.09 metric ton

    i hope this is right.
     
  5. Jan 31, 2006 #4
    hey! thanks allot for the information
    but i tried that answer and it said its wrong :frown:
    oh well dont worry i'll keep on tryin because i'm at work here
    and i have other online problems to do also though
     
  6. Jan 31, 2006 #5

    HallsofIvy

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    It's much too much information! It is better suggest steps to take than simply solve the problem for him.
     
  7. Jan 31, 2006 #6

    DaveC426913

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    Not where I come from it isn't!:bugeye:

    Is that some new "pi=3" Kansas law passed?
     
  8. Jan 31, 2006 #7

    Hootenanny

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    1 metric ton or tonne is 1000 kg. I think you calcs may be correct now.
     
  9. Jan 31, 2006 #8

    Yeah that why I was confised.. haha I was like " :yuck: when did 103 kg became = 1 metric ton.." hahha
    Since it was in teh question I used it...
    anyway the answer should be..

    81600000 kg / 1000 kg = 81600 Ton
     
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