Estimating water volume(so lost)

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Homework Help Overview

The problem involves calculating the volume of water that fell on a city during a rainstorm, given specific dimensions and rainfall measurements. The subject area pertains to fluid dynamics and volume calculations in physics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conversion of measurements and the calculation of total volume based on the dimensions provided. There are attempts to clarify the definition of a metric ton and its relation to kilograms, as well as the conversion of volume from cubic meters to cubic centimeters.

Discussion Status

Some participants have provided calculations and expressed uncertainty about the correctness of their results. There is a mix of interpretations regarding the definition of a metric ton, with some questioning the original poster's calculations and others suggesting that the calculations may be correct. The discussion remains open with no explicit consensus reached.

Contextual Notes

Participants note confusion regarding the definition of a metric ton, with some referencing a discrepancy in the conversion factor used. There is also mention of the original poster's frustration with receiving incorrect feedback on their answer.

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A violent rainstorm dumps 1.7 cm of rain on a city 6.0 km wide and 8.0 km long in a 3.0 hr period. How many metric tons (1 ton = 103 kg) of water fell on the city? [1 cm3 of water has a mass of 1 g = 10-3 kg.]

any help would be greatly apreciated!
 
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Think about defining density.
 
1.7 cm =.017m=thickness
Width =6 km =6000m
length = 8 km =8000 m

t0al volume = .017 x 6000 x 8000
=81600 m^3
=81600 x (100 cm)3
=81600 x 1000000 cm^3
=81600000000 cm3


since 1cm^3 = 1 gram

81600000000 cm^3 = 81600000000 gm =81600000 kg

since 1 metric ton =103 kg
81600000 kg = 81600000 kg / 103 kg =

792233.09 metric ton

i hope this is right.
 
Ishu said:
1.7 cm =.017m=thickness
Width =6 km =6000m
length = 8 km =8000 m

t0al volume = .017 x 6000 x 8000
=81600 m^3
=81600 x (100 cm)3
=81600 x 1000000 cm^3
=81600000000 cm3


since 1cm^3 = 1 gram

81600000000 cm^3 = 81600000000 gm =81600000 kg

since 1 metric ton =103 kg
81600000 kg = 81600000 kg / 103 kg =

792233.09 metric ton

i hope this is right.

hey! thanks allot for the information
but i tried that answer and it said its wrong :frown:
oh well don't worry i'll keep on tryin because I'm at work here
and i have other online problems to do also though
 
Ishu said:
i hope this is right.

It's much too much information! It is better suggest steps to take than simply solve the problem for him.
 
Ishu said:
since 1 metric ton =103 kg
Not where I come from it isn't!:bugeye:

Is that some new "pi=3" Kansas law passed?
 
1 metric ton or tonne is 1000 kg. I think you calcs may be correct now.
 
Hootenanny said:
1 metric ton or tonne is 1000 kg. I think you calcs may be correct now.


Yeah that why I was confised.. haha I was like " when did 103 kg became = 1 metric ton.." hahha
Since it was in the question I used it...
anyway the answer should be..

81600000 kg / 1000 kg = 81600 Ton
 

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