Estimating Work on the Ferris Wheel: George Washington Gale Ferris Jr.

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The discussion centers on estimating the work required for the machinery of the Ferris wheel designed by George Washington Gale Ferris Jr. The wheel, with a diameter of 76 meters and 36 wooden cars, operates at a constant angular speed, completing a rotation in 2 minutes. Two methods for calculating work were proposed: using the inertia and angular velocities, and torque with angular displacement. The conclusion reached is that once the Ferris wheel is fully loaded, it does not perform additional work during the ride, as the system operates at constant speed.

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I've been thinking about this problem for the last half hour, but can't seem to come up with a way of finding a solution. Maybe some of you can help.

"George Washington Gale Ferris. Jr., a civil engineering graduate from RPI, built the original Ferris wheel. The wheel carried 36 wooden cars, each holding up to 60 passengers, around a circle 76m in diameter. The cars were loaded 6 at a time, and once all 36 cars were full, the wheel made a complete rotation at constant angular speed in about 2 min. Estimate the amount fo work that was required of the machinery to rotate the passengers alone."

I approached this problems through two methods:

1) W = (1/2)(I)(wf^2 - wi^2), where I is the inertia, wf is the final angular velocity and wi is the initial angular velocity, and

2) W = t(thetaf - thetai), where t is the torque, thetaf is the final angle and thetai is the initial angle.

But both attempts give me zero (which, for some reason, doesn't seem liek the right answer). If the ferris wheel is traveling at a constant angular speed, then shouldn't wi = wf, and therefore W = 0? And, if it completes a revolution, shouldn't thetaf = thetai and, also, W = 0?

Thanks for any help.
 
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Did you post this problem twice? I just replied to the same problem somewhere else.

This is probably where it belongs

I think you need to focus on the loading process. Once the wheel is loaded it should be finished working. The 2 min ride is work free.
 
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