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silentsaber

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HI, i have three problems that i have tried but failed here they are

a)find the final angular speed b) find the time it takes to turn 4 revolutions

2.) A potter's wheel is a stone disk 85 cm in diameter with a mass of 120 kg. If the potter's foot pushes at the outer edge of the initially stationary wheel with a 80 N force for one-eighth of a revolution, what will be the final speed? Use the work-energy theorem.

3.)A 320 kg motorcycle includes two wheels, each of which is 52 cm in diameter and has rotational inertia 2.1 kg·m2. The cycle and its 74 kg rider are coasting at 87 km/h on a flat road when they encounter a hill. If the cycle rolls up the hill with no applied power and no significant internal friction, what vertical height will it reach?

1.) omega final^2= omega initial squared +2a(angular position)/ omega final=omega initial +at

2.) I used W=1/2I wf^2 -1/2I wi^2

3.) tried using the v center of mass= sqrt of (2mgh)/(M+I/(R^2))

for the first one i plugged in everything but i get the wrong answer i think its because of the revolutions, but i changed that to rad and the 20rpm/s i left it since the answer has to be in rpm

2.) SInce it told me to use the work energy theorem i tried pluggin in the 1/2mr^2 for I sicne its a disk and 80N for W as well as the 120kg for mass but... i keep getting the wrong answer... did i use the wrong equation or?

3.) for number I am not sure if the equation is the correct one.. i tried plugging in the numbers but then for mass i plugged in 320+74 too have the combined mass of 394 and changed the 87 km/h to 24.2 m/s but the answer was wrong so that didnt work out...so I am stumped...

thank you in advance

## Homework Statement

**1.) A wheel turns through 4 revolutions while being accelerated from rest at 20rpm/s.**__SOLVED__a)find the final angular speed b) find the time it takes to turn 4 revolutions

2.) A potter's wheel is a stone disk 85 cm in diameter with a mass of 120 kg. If the potter's foot pushes at the outer edge of the initially stationary wheel with a 80 N force for one-eighth of a revolution, what will be the final speed? Use the work-energy theorem.

3.)A 320 kg motorcycle includes two wheels, each of which is 52 cm in diameter and has rotational inertia 2.1 kg·m2. The cycle and its 74 kg rider are coasting at 87 km/h on a flat road when they encounter a hill. If the cycle rolls up the hill with no applied power and no significant internal friction, what vertical height will it reach?

## Homework Equations

1.) omega final^2= omega initial squared +2a(angular position)/ omega final=omega initial +at

2.) I used W=1/2I wf^2 -1/2I wi^2

3.) tried using the v center of mass= sqrt of (2mgh)/(M+I/(R^2))

## The Attempt at a Solution

for the first one i plugged in everything but i get the wrong answer i think its because of the revolutions, but i changed that to rad and the 20rpm/s i left it since the answer has to be in rpm

2.) SInce it told me to use the work energy theorem i tried pluggin in the 1/2mr^2 for I sicne its a disk and 80N for W as well as the 120kg for mass but... i keep getting the wrong answer... did i use the wrong equation or?

3.) for number I am not sure if the equation is the correct one.. i tried plugging in the numbers but then for mass i plugged in 320+74 too have the combined mass of 394 and changed the 87 km/h to 24.2 m/s but the answer was wrong so that didnt work out...so I am stumped...

thank you in advance

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