Solving the Ferris Wheel Problem: Estimating Work Requirement

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SUMMARY

The Ferris Wheel problem involves estimating the work required to rotate passengers in a Ferris wheel designed by George Washington Gale Ferris Jr. The wheel has a diameter of 76 meters and carries 36 cars, each holding 60 passengers. Two methods were proposed for calculating work: using the inertia formula W = (1/2)(I)(wf^2 - wi^2) and the torque formula W = t(thetaf - thetai). However, both methods resulted in zero work due to the constant angular speed of the wheel, indicating that no additional work is required once the wheel is loaded and in motion.

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This discussion is beneficial for physics students, mechanical engineers, and anyone interested in the mechanics of amusement rides, particularly those analyzing work and energy in rotational systems.

jonlevi68
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I've been thinking about this problem for the last half hour, but can't seem to come up with a way of finding a solution. Maybe some of you can help.

"George Washington Gale Ferris. Jr., a civil engineering graduate from RPI, built the original Ferris wheel. The wheel carried 36 wooden cars, each holding up to 60 passengers, around a circle 76m in diameter. The cars were loaded 6 at a time, and once all 36 cars were full, the wheel made a complete rotation at constant angular speed in about 2 min. Estimate the amount fo work that was required of the machinery to rotate the passengers alone."

I approached this problems through two methods:

1) W = (1/2)(I)(wf^2 - wi^2), where I is the inertia, wf is the final angular velocity and wi is the initial angular velocity, and

2) W = t(thetaf - thetai), where t is the torque, thetaf is the final angle and thetai is the initial angle.

But both attempts give me zero (which, for some reason, doesn't seem liek the right answer). If the ferris wheel is traveling at a constant angular speed, then shouldn't wi = wf, and therefore W = 0? And, if it completes a revolution, shouldn't thetaf = thetai and, also, W = 0?

Thanks for any help.
 
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I think you need to focus on the loading process. Once the wheel is loaded it should be finished working. The 2 min ride is work free.
 

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