Evaluate the value of trigonometry

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    Trigonometry Value
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Homework Help Overview

The discussion revolves around evaluating the product of several sine functions with angles expressed in terms of π/62. The subject area is trigonometry, focusing on identities and properties of sine and cosine functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore various identities and properties of sine and cosine, including attempts to transform the product into a cosine form. Some participants suggest looking for patterns in the angles, while others question the setup of the problem, particularly the denominator.

Discussion Status

The discussion is active, with participants sharing insights and identities from external sources. There is a mix of approaches being explored, and while some participants express confusion, others provide clues that seem to guide the conversation toward potential solutions.

Contextual Notes

There is a question regarding whether the denominator in the sine terms should be 62 or 64, with some participants noting that the problem works better with 62. The original poster confirms the denominator is indeed 62.

harimakenji
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Homework Statement


evaluate
sin (π / 62) . sin (15π/62). sin(23π/62). sin(27π/62) . sin(29π/62)


Homework Equations


trigonometry


The Attempt at a Solution


Tried to change it to cos but failed, tried to use 2 sin A sin B identity and failed again

Thank you very much
 
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If you use the property that [tex]sin(x)=cos(\pi/2-x)[/tex] you can get a nice pattern going. See if that helps.
 
sin (π / 62) . sin (15π/62). sin(23π/62). sin(27π/62) . sin(29π/62) = cos (30π / 62). cos(16π/62). cos (8π/62). cos(4π/62). cos(2π/62)

I see no pattern. Is there a nice pattern?
 
You don't notice a pattern happening? 2,4,8,16,... now you have 30 instead of 32, but you can change it to 32 with another identity.
 
I noticed that but lost because of 30 but now I get it from your clue.

cos (30π / 62) = - cos (32π / 62), then it becomes: - (cos x) . (cos 2x). cos(4x). cos (8x). cos (16x). How to continue that?
 
harimakenji, I've done stuff like this in an advanced class in high school (in Australia it is called extension 2 mathematics) but usually they first make us prove the given identity as vela has posted and then finally using the formula to evaluate the question that you've been given. Are you sure this question wasn't a continuation from a bigger problem?
 
harimakenji said:

Homework Statement


evaluate
sin (π / 62) . sin (15π/62). sin(23π/62). sin(27π/62) . sin(29π/62)
Can you double-check, is the denominator in all those terms supposed to be 62 or 64?
 
Redbelly98 said:
Can you double-check, is the denominator in all those terms supposed to be 62 or 64?

Actually, it works even more nicely being 62 than 64 :wink:
 
  • #10
vela said:
Wikipedia cites a relevant identity:

http://en.wikipedia.org/wiki/List_of_trigonometric_identities#Identities_without_variables

I had never seen it before, though.

I also had never seen it before, phew

Mentallic said:
harimakenji, I've done stuff like this in an advanced class in high school (in Australia it is called extension 2 mathematics) but usually they first make us prove the given identity as vela has posted and then finally using the formula to evaluate the question that you've been given. Are you sure this question wasn't a continuation from a bigger problem?

The question is just like this, no bigger problem. This is the question for my brother in grade 11.

Redbelly98 said:
Can you double-check, is the denominator in all those terms supposed to be 62 or 64?
It is 62. I've checked the result using calculator and it is very nice result, 1 / 32


I can solve this question using the link given by vela. I can't do this without all the help here. Thank you very much for the help (vela, mentallic, redbelly98). I really appreciate all the things I got from here. Once again, thank you.
 

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