Evaluating a quartic polynomial.

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The discussion focuses on evaluating the quartic polynomial equation \(\frac{(2N-1)^2}{N(1-N)}=Ce^t\) using the substitution \(u=N-\frac{1}{2}\). Participants emphasize the importance of substituting \(N\) with \(u + \frac{1}{2}\) to simplify the expression. The suggested substitutions, \(2N-1=2u\) and \(N=\frac{2u+1}{2}\), are critical for transforming the equation into a more manageable form. This approach allows for a clearer path to finding the roots of the polynomial by hand.

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I want to find the root(for N) of this equation:

\frac{(2N-1)^2}{N(1-N)}=Ce^t

The hint says "consider taking a substitution u=N-1/2" ...which is the top bit of the fraction. But what does take a substitution here mean ?

This is a part of a loooong modelling problem which involved an ugly *** integral and gave this equation as the result. I've never evaluated a "quartic equation" so I'm a bit confused about the process.

I have the answer from wolfram so am looking for guidance on how to work it out by hand.
 
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\frac{(2N-1)^2}{N(1-N)}=Ce^tFor the numerator, use the substitution:
2N-1=2uFor the denominator, use the substitution:
N=\frac{2u+1}{2}
 
What is stopping you from substituting N = u + 1/2 into the expression on the left? It is simple algebra. If you actually DO it you will see how to proceed.

RGV
 

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