Evaluating [d^2/dx^2, x] on an f(x)

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1. Evaluate the commutator [d^2/dx^2, x] by applying the operators to an arbitrary function f(x).
 
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That's (x*f(x))''-x*f'''(x), isn't it? What's the result?
 


I just found the answer it is: 2 d/dx
 


I believe that's correct. Wasn't so hard, was it?
 

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