asmani Messages 104 Reaction score 0 Thread starter Nov 1, 2011 #1 Evaluate the following integral using the residue theorem: Any hint?
lurflurf Homework Helper Messages 2,459 Reaction score 159 Nov 1, 2011 #2 2i sin(x)=eix-e-ix and (n+1)undu=dun+1 with u=eix is (n+1)einxdeix=dei(n+1)x
asmani Messages 104 Reaction score 0 Nov 2, 2011 #3 Sorry, I can't see how to use these facts. Can you give any further hint, please? Besides, what contour should be chosen? Thanks Last edited: Nov 2, 2011
Sorry, I can't see how to use these facts. Can you give any further hint, please? Besides, what contour should be chosen? Thanks
lurflurf Homework Helper Messages 2,459 Reaction score 159 Nov 2, 2011 #4 contour is unit circle let z=ei x dx=dz/(i z) sin(x)=((z-1/z)/(2i)) sin2n(x)=((z-1/z)/(2i))2n [tex]\int_0^\pi \sin^{2n}(x) dx=\frac{1}{2}\int_{-\pi}^\pi \sin^{2n}(x) dx=\oint_{|z|=1}\left( \frac{z-\frac{1}{z}}{2i}\right)^{2n}\frac{dz}{2i z}[/tex]
contour is unit circle let z=ei x dx=dz/(i z) sin(x)=((z-1/z)/(2i)) sin2n(x)=((z-1/z)/(2i))2n [tex]\int_0^\pi \sin^{2n}(x) dx=\frac{1}{2}\int_{-\pi}^\pi \sin^{2n}(x) dx=\oint_{|z|=1}\left( \frac{z-\frac{1}{z}}{2i}\right)^{2n}\frac{dz}{2i z}[/tex]