Even, Odd,or Neither Odd or Even Function

  • Thread starter Thread starter albert2008
  • Start date Start date
  • Tags Tags
    even Function
Click For Summary

Homework Help Overview

The discussion revolves around determining whether the function h(x) = 2x - x² is even, odd, or neither. Participants explore the definitions of even and odd functions and analyze the function's behavior under these definitions.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants examine the calculations for h(-x) and compare it to h(x) and -h(x). Questions arise regarding the definitions of even and odd functions and the reasoning behind classifying h as neither.

Discussion Status

Some participants provide definitions and properties of even and odd functions, while others seek clarification on the original poster's confusion. There is an ongoing exploration of the function's characteristics without a clear consensus on the interpretation of the results.

Contextual Notes

Participants note that the original poster initially believed the function to be odd and express a desire for alternative explanations to understand the classification better. There is mention of potential pitfalls in numerical testing of the function.

albert2008
Messages
12
Reaction score
0
Dear People,
I'm sorry to put up such an easy question. But would someone please explain a little further.

h(x)=2x-x2
h(-x)=2(x)-(-x)2 = -2x-x2

Since h(-x) doesn't equal h(x) and h(-x) doens't equal -h(x), we conclude that H is neither even nor odd.

I would have put that this fuction is odd on the test. Why is it neither? The answer is above I was wondering if someone could explain in a different way that i may be able to undestand.
 
Physics news on Phys.org
Albert2008 said:
I would have put that this fuction is odd on the test. Why is it neither? The answer is above I was wondering if someone could explain in a different way that i may be able to undestand.
Why would you have said that it was odd? What is the definition of an odd function?
 
An odd function is a function (behaving like an odd power of x) for which f(-x)=-f(x).
An even function is a function (behaving like an even power of x) for which f(-x)=f(x).

Any function can be resolved into its even and odd components:

[tex]f(x) = f_{odd}(x) + f_{even}(x)[/tex]
where
[tex]f_{even}(x) = \frac{f(x)+f(-x)}{2}[/tex]
and
[tex]f_{odd}(x) = \frac{f(x)-f(-x)}{2}[/tex]

Note for example that the even and odd components of the exponential function are the hyperbolic trig functions.
[tex]e^x = \cosh(x)+\sinh(x)[/tex]

The use of the "even" and "odd" terms comes from the even and odd components of a polynomial which will be respectively the sum of the even degree terms and the sum of the odd degree terms.

Similarly with "infinite polynomials" i.e. the power series expansion of analytic functions.

FWIW
Another way to look at this is to define oddness and evenness in terms of commutativity or anti-commutativity with the negation function under composition:

[itex]f[/itex] is even iff [itex]\{f,N\}_\circ \equiv f\circ N + N\circ f = 0[/itex]

[itex]f[/itex] is odd iff [itex][f,N]_\circ \equiv f\circ N - N\circ f = 0[/itex]

where [itex]N(x) = -x[/itex]
 
Dear Dr. Baugh,
Thank you so much for taking time to answer my question.
 
If you don't see why algebraically why it's not odd, try to numerically. Just keep plugging numbers into h(x) a d h(-x) and see if h(-x)=-h(x). Be warned, your teacher probably picked this function because for what would be most people's first two choices of numbers to plug in, it would <i>seem</i> like h(x) is odd.

Then when you find an x that contradicts h(-x)=-h(x), you'll probably see <i>why</i> it didn't hold.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
7
Views
3K
Replies
8
Views
5K
Replies
5
Views
2K
  • · Replies 28 ·
Replies
28
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K