Domain of a composite function

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ilii
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Homework Statement


Given the Functions
f(x)=4x-1
g(x)=3-2x^2
h(x)= sqrt (x+5)

What is the domain of h(g(x))?

Homework Equations



the subject is finding the domain of a composite function

The Attempt at a Solution


I don't understand what I have to 'bring over' from g(x). I think x cannot equal zero for g(x). If someone could post a structured list of steps I need to take to find the domain of a composite function, it would be much appreciated.

thank you
 
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The domain of a composite function [itex](f \circ g)(x)=f(g(x))[/itex] is defined as [itex]D(f\circ g)=\{x \epsilon D(g) | g(x) \epsilon D(f) \}[/itex]. So you should find the domains of f and g and check that for what subset of the domain of g, it gives values in the domain of f.
 
ilii said:

Homework Statement


Given the Functions
f(x)=4x-1
g(x)=3-2x^2
h(x)= sqrt (x+5)

What is the domain of h(g(x))?

Homework Equations



the subject is finding the domain of a composite function

The Attempt at a Solution


I don't understand what I have to 'bring over' from g(x). I think x cannot equal zero for g(x).

thank you

Why do you think that? ##g(x)## is just a polynomial. What' wrong with ##g(0)##?
What is the formula for ##h(g(x))##? What values of ##x## work in that?
 
The domain of square root is "numbers greater than or equal to 0". h(x)= sqrt(x- 5) so the domain of h is "[itex]x- 5\ge 0[/itex] or [itex]x\ge 5[/itex]. That means that [itex]g(x)= 3- 2x^2[/itex] must give only values greater than or equal to 5. Can you solve [itex]3- 2x^2\ge 5[/itex]?
 
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thanks everyone I understand it much better now :D