Eventual boundedness of nth derivative of an analytic function in L2 norm

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SUMMARY

The discussion focuses on proving that for an analytic function \( f(x) \), there exists a constant \( c \) such that the inequality \( || f^{(n)} (x) || \leq c n! || f(x) || \) holds for sufficiently large \( n \). The user attempts to leverage Taylor series and inequalities but struggles to reach a conclusion. The goal is to establish that there exists an \( N \) such that for all \( n > N \) and \( x \in (-R, R) \), the inequality \( | f^{(n)} (x) | \leq c n! | f(x) | \) is valid for analytic functions.

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  • Understanding of analytic functions and their properties
  • Familiarity with Taylor series expansions
  • Knowledge of L2 norms and integrals
  • Basic concepts of inequalities in mathematical analysis
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Mathematicians, analysts, and students studying complex analysis or functional analysis, particularly those interested in the behavior of derivatives of analytic functions.

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I'm trying to show that if f(x) is analytic, then for large enough n,

|| f^{(n)} (x) || \leq c n! || f(x) ||,

where
|| f ||^2=\int_a^b{|f|^2}dx

and f^{(n)} denotes the nth derivative.

I tried to use the Taylor series, and then manipulated some inequalities, but I wasn't getting anywhere.

Any ideas?

Thanks
 
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I figure I can reduce the problem to showing that there is an N such that for all n>N, and for all x\in(-R,R),

<br /> | f^{(n)} (x) | \leq c n! | f(x) |<br />.


Is this necessarily true for analytic functions?
 
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