Exact solution to advection equation in spherical coordinates

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SUMMARY

The exact solution to the advection equation in spherical coordinates is derived from the equation \(\frac{\partial{\phi}}{\partial{t}} + \frac{u}{r^2}\frac{\partial{}}{\partial{r}}r^2\phi = 0\), leading to the separation of variables approach. The solution is expressed as \(\phi = Ae^{\frac{\lambda}{u}(r-ut)-2}\), where \(u\) is a constant velocity. The discussion emphasizes the importance of verifying the solution by back-substituting into the differential equation to confirm its validity. The general solution may also involve arbitrary functions typical of first-order partial differential equations (PDEs).

PREREQUISITES
  • Understanding of partial differential equations (PDEs)
  • Familiarity with separation of variables technique
  • Knowledge of spherical coordinates in mathematical physics
  • Basic concepts of boundary and initial value problems
NEXT STEPS
  • Study the method of characteristics for first-order PDEs
  • Explore the implications of boundary conditions on solutions
  • Learn about the Laplace transform in solving PDEs
  • Investigate the differences in solutions between Cartesian and spherical coordinates
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Mathematicians, physicists, and engineers working with fluid dynamics, particularly those focusing on the behavior of wave equations and advection phenomena in spherical coordinates.

lostidentity
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I've been trying to find the exact solution to the advection equation in spherical coordinates given below

[tex]\frac{\partial{\phi}}{\partial{t}} + \frac{u}{r^2}\frac{\partial{}}{\partial{r}}r^2\phi = 0[/tex]

Where the velocity u is a constant. First I tried to expand the second term using product rule and then apply the separation of variables, which gives me the following.

Separation of variables

[tex]\phi = R(r)T(t)[/tex]

[tex]\frac{1}{T}\frac{dT}{dt} = -\frac{u}{R}\frac{dR}{dr} - \frac{2u}{r} = -\lambda^2[/tex]

And the final answer is

[tex]\phi = Ae^{\frac{\lambda}{u}(r-ut)-2}[/tex]

Wonder if this is correct? For Cartsesian coordinates I know the solution is very simple just [tex]\phi=\phi_0(x-ut)[/tex] where [tex]\phi_0[/tex] is the initial profile for phi.
 
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lostidentity said:
Wonder if this is correct?

Hi. You need to remember always if needed and no complications, you can back-substitute your presumptive solution into the DE. If it satisfies the DE, then it is a correct solution, barring any initial, boundary or other requirements. Do you mean the general solution? If so than I think it would be some arbitrary function of a function such as C(g(x,y)) as normally encountered in first order PDEs.
 
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