Exam : find the minimum value of this function and constrant

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Homework Help Overview

The problem involves finding the minimum value of the expression \(\sqrt{x^2 + a^2} + \sqrt{y^2 + b^2}\) under the constraints \(x + y = 6\sqrt{2}\) and \(a + b = 6\sqrt{2}\). The context is rooted in optimization techniques, specifically involving Lagrange multipliers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of Lagrange multipliers as a potential method for solving the problem. Some suggest simplifying the problem using the relationship between \(x\) and \(y\). Others express concern about the appropriateness of providing help for what may be a take-home exam.

Discussion Status

The discussion is ongoing, with various participants offering insights into possible methods and expressing differing views on the appropriateness of assistance. Some participants have provided hints about techniques, while others have raised questions about the nature of the exam.

Contextual Notes

There is a mention of constraints regarding the nature of the exam, with some participants questioning whether it is appropriate to provide help. Additionally, the original poster expresses frustration about previous unanswered posts, indicating a desire for engagement and support.

~Scott~
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Homework Statement


Given
[tex]x+y = 6\sqrt2[/tex]
[tex]a + b = 6\sqrt 2[/tex]
Find minimum value of [tex]\sqrt{x^2 + a^2} + \sqrt{y^2+b^2}[/tex]

2. The attempt at a solution
I had plotted the [tex]f(x,y)[/tex] with constant [tex]a ,b[/tex]
And that's all. I don't realize how to do this.

Any comment will be appreciated
 
Last edited:
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I don't know where on Earth you found this question, but one can find the minimum value. The key step is to notice that you can simplify the total derivative considerably using the relation between x and y. That, together with...

But I've probably said enough. I figure this is a take-home exam or something.
 
Last edited:
If this is a take home exam, we really shouldn't help you.
 
It's a Lagrange multiplier problem with two constraints. Try that technique.
 
Let me introduce myself. Sorry to take pity on me.
I graduated from Physics and now studying in computer science.

Of course, I studied Lagrange multiplier in classical mechanics.

I always spend my free time to enjoy mathematics and computing.
I found this problem from math.or.th age not over 15.
And I never expect that I have to use Lagrange multiplier.

You can check my post about GPU/CUDA topics that is my first post.
And now it's finish without any reply from this forum.

And second post of mine is about gaussian gun. Again no one reply.

The third one is this about lagrange multiplier.

Guess what.
Your people totally look down on me just because you known how to solve it
What about two questions of mine ?

I know your situation that many lazy students exploit this forum for their benefit.
It's ok, but please count me out.

If anyone would like me to identify myself as a master degree in computer science. Just sent me your PM and I will show it to you.

Thanks everyone who show me the topics of Lagrange multiplier.
 
~Scott~ said:
Let me introduce myself. Sorry to take pity on me.
I graduated from Physics and now studying in computer science.

Of course, I studied Lagrange multiplier in classical mechanics.

I always spend my free time to enjoy mathematics and computing.
I found this problem from math.or.th age not over 15.
And I never expect that I have to use Lagrange multiplier.

You can check my post about GPU/CUDA topics that is my first post.
And now it's finish without any reply from this forum.

And second post of mine is about gaussian gun. Again no one reply.

The third one is this about lagrange multiplier.

Guess what.
Your people totally look down on me just because you known how to solve it
What about two questions of mine ?

I know your situation that many lazy students exploit this forum for their benefit.
It's ok, but please count me out.

If anyone would like me to identify myself as a master degree in computer science. Just sent me your PM and I will show it to you.

Thanks everyone who show me the topics of Lagrange multiplier.

There is another way: substitute y = c-x into f(x,y), where c = 6*sqrt(2). The result F(x) = f(x,c-x) is a univariate function, and can be minimized by setting its derivative to zero; in fact, we know the function F is strictly convex, so any stationary point is a global minimum.

Finding the derivative is not too hard, but solving the equation F'(x) = 0 for x is a bit nasty. (Here, I am assuming that a and b are not variables, but are just some constants that satisfy a+b=c.) It turns out that the solution is just x = a (when the relationship between a and b is exploited). I took the easy way out, and let Maple 11 solve the equations for me; doing the problem by hand would be difficult.

RGV
 
Thank you RGV.
I will check it.
 

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