Example of Lebesgue Integral but not Riemann Integrable

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Discussion Overview

The discussion revolves around identifying examples of functions that are Lebesgue integrable but not Riemann integrable. Participants explore various functions and their properties, focusing on theoretical aspects and specific examples.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants suggest the characteristic function of a nonempty measurable set that is discontinuous everywhere as a potential example.
  • One participant mentions a specific example of a function that is 1 for irrational numbers and 0 for rational numbers, explaining its Lebesgue integrability and lack of Riemann integrability due to the nature of rational and irrational numbers in any interval.
  • Another participant introduces the characteristic function of the set of rational numbers within the interval [0,1], noting its Lebesgue integral is 0 and its discontinuity at uncountably many points prevents it from being Riemann integrable.
  • There is a request for more complicated examples, with a mention of the Dirichlet function, which is discontinuous everywhere.
  • One participant seeks examples where both the set of discontinuities and the set of continuities have non-zero measure, referencing a type of Cantor set with positive measure.

Areas of Agreement / Disagreement

Participants express various viewpoints on examples of Lebesgue integrable functions that are not Riemann integrable, with no consensus on a single example or approach. Multiple competing views and examples are presented.

Contextual Notes

Some examples rely on specific properties of functions and sets, such as the nature of discontinuities and the measure of sets involved, which may not be universally agreed upon or fully explored.

Nusc
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What's Example of Lebesgue Integrable function which is not Riemann Integrable?
 
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There are plenty. Can you think of a characteristic function of a nonempty measurable set (of finite measure) that is discontinuous everywhere? Why will this do?
 
There's example 7.4 on page 145 -- in the limit, this is the classic example of a non-Riemann-integrable function.

But I don't understand why this will do.
 
Nusc said:
There's example 7.4 on page 145 -- in the limit, this is the classic example of a non-Riemann-integrable function.

But I don't understand why this will do.
I get annoyed when people refer to examples in specific books- do they expect everyone to have the book in front of them? But here, you don't even say what book!

The simplest example of a Lebesque integrable function that is not Riemann integrable is f(x)= 1 if x is irrational, 0 if x is rational.

It is trivially Lebesque integrable: the set of rational numbers is countable, so has measure 0. f = 1 almost everywhere so is Lebesque integrable and its integral, from 0 to 1, is 1.

But if no matter how we divide the interval from x= 0 to x= 1 into intervals, every interval contains both rational and irrational numbers: the "lower sum" is always 0 and the "upper sum" is always 1. As we increase the number of intervals to infinity, those do NOT converge.
 
Consider the following set $A= Q \cap [0,1]$. Where Q is the set of rational numbers of course. Now consider the characteristic function of $A$ denoted $X_A$ defined as follow: $X_A(x)=0$ when $x \in A$ and $x=0$ otherwise. Since this function is almost zero everywhere, then its Lebesgue integral is clearly 0. However, it is easily proved that $X_A$ is not Riemann integrable. As an argument but not proof to support this, the function is discontinuous at uncountable number of points.

Vignon S. Oussa
 
Last edited:
Could you give us another, more complicated example? It seems like the Dirichlet function is everywhere!

thanks!
riesling
 
riesling said:
Could you give us another, more complicated example? It seems like the Dirichlet function is everywhere!

thanks!
riesling

What kind of example do you want?? You can also have

[tex]f(x)=x~\text{for}~x\neq \mathbb{Q}~\text{and}~f(x)=0~\text{otherwise}[/tex]
 
Thanks! I'm looking for some where the set of discontinuities and the set of continuities are both of non-zero measure...Is that posible...I know of a type of Cantor set which has positive measure...are there others?
 

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