Examples in lin.alg. where closure/addition axioms don't hold

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The discussion focuses on finding subsets in a coordinate space that demonstrate specific closure properties related to addition and multiplication. For part (a), participants suggest that complex numbers might be relevant, but caution is advised regarding their use as vector spaces over different fields. The initial examples proposed for parts (b) and (c) are critiqued, indicating that larger sets may be necessary to satisfy the axioms. A methodical approach is recommended, starting with an arbitrary element and iteratively checking which closure axiom is satisfied. The conversation emphasizes the importance of understanding the implications of vector space definitions on the closure properties.
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Homework Statement



Find examples of subsets in a coordinate space where:

(a) closure addition axiom doesn't hold but closure multiplication does hold,

(b) closure addition axiom does hold but clouser multiplication doesn't hold,

(c) where neither hold.

Homework Equations



None in particular, but what he means by closure addition and multiplication axioms is that you can add two elements of the subset together and that will still be an element of the subset. For multiplication, you're supposed to be able to multiply the element with any number in R, and it the product will also belong to the subset.

The Attempt at a Solution


[/B]
I'm thinking complex numbers have something to do with this. (c) I think could be {-3, -2, 1}, (b) is something like {-3, -2, -1}, but it's (a) that I'm worried about. I simply have no idea for (a).

edit, scratch that I'm being silly about (b)... it's very wrong.
 
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You'll need larger sets.
You can use complex numbers, but be careful if you use them as vector space over the real numbers or as vector space over complex numbers (this influences the options you have for multiplication, and also the dimension of the vector space).

A good way to start for (a) and (b): take an arbitrary element (like "1"), figure out what else has to be in your set to satisfy one of the closure axioms. Then see if the other one is satisfied, if yes you'll have to add another element to your set (because removing one does not work) and repeat the step.
 

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