Existence and Uniqueness of Inverses

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Discussion Overview

The discussion centers on the existence and uniqueness of inverses in linear algebra, particularly focusing on the conditions under which the equation Ax = b has solutions. Participants explore the implications of column spanning and linear independence on the existence of right and left inverses, respectively.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant states that Ax = b has at least one solution for every b if and only if the columns of A span Rm, questioning the existence of a right inverse C such that AC = I under the condition m ≤ n.
  • Another participant discusses uniqueness, asserting that Ax = b has at most one solution for every b if and only if the columns of A are linearly independent, seeking clarification on the existence of a left inverse B such that BA = I when m ≥ n.
  • A participant proposes a scenario involving linearly dependent columns and asks whether a non-zero x can be found such that Ax = 0, hinting at the implications for the existence of inverses.
  • Another participant challenges the interpretation of A as a column vector in the context of linear dependence, suggesting a misreading of the original question.
  • A request is made for an example of a 2x2 matrix with linearly dependent columns to illustrate the concept further.

Areas of Agreement / Disagreement

Participants express uncertainty and seek clarification on the reasoning behind the existence and uniqueness of inverses, indicating that multiple views and interpretations are present without a consensus on the explanations provided.

Contextual Notes

Participants have not fully resolved the implications of linear dependence and independence on the existence of inverses, and there are missing assumptions regarding the definitions of the terms used.

jolly_math
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Existence: Ax = b has at least 1 solution x for every b if and only if the columns span Rm. I don't understand why then A has a right inverse C such that AC = I, and why this is only possible if m≤n.

Uniqueness: Ax = b has at most 1 solution x for every b if and only if the columns are linearly independent. I don't understand why then A has a n x m left inverse B such that BA = I, and why this is only possible if m≥n.

Could anyone explain the logic behind this? Thank you.
 
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Let's start with uniqueness. Suppose A has two columns that are linearly dependent. Can you find x that's not equal to 0 with Ax=0? Hint: it only has two nonzero elements
 
Office_Shredder said:
Let's start with uniqueness. Suppose A has two columns that are linearly dependent. Can you find x that's not equal to 0 with Ax=0? Hint: it only has two nonzero elements
No. A would be a column vector, and only x=0 would work. Why does this lead to the left inverse B such that BA = I, and why it is only possible if m≥n?

Thank you.
 
jolly_math said:
No. A would be a column vector

It's not. You might have misread my question, give it another look :)
 
I'm not sure what the answer is, could you explain the reasoning? Thank you.
 
Can you write out a 2x2 matrix which has two columns that are linearly dependent?
 

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