Undergrad Existence and Uniqueness of Inverses

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SUMMARY

The discussion centers on the existence and uniqueness of inverses in linear algebra, specifically regarding the conditions under which the equation Ax = b has solutions. It is established that Ax = b has at least one solution for every b if the columns of matrix A span R^m, which implies the existence of a right inverse C such that AC = I, necessitating that m ≤ n. Additionally, Ax = b has at most one solution if the columns of A are linearly independent, leading to the existence of a left inverse B such that BA = I, which is only possible if m ≥ n.

PREREQUISITES
  • Understanding of linear algebra concepts such as matrix dimensions and spans
  • Familiarity with the definitions of left and right inverses of matrices
  • Knowledge of linear independence and dependence of vectors
  • Basic proficiency in solving linear equations
NEXT STEPS
  • Study the properties of matrix inverses in linear algebra
  • Learn about the implications of the Rank-Nullity Theorem
  • Explore examples of linearly dependent and independent vectors in R^n
  • Investigate the conditions for the existence of unique solutions in systems of linear equations
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Students and educators in mathematics, particularly those focusing on linear algebra, as well as professionals in fields requiring mathematical modeling and problem-solving skills.

jolly_math
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Existence: Ax = b has at least 1 solution x for every b if and only if the columns span Rm. I don't understand why then A has a right inverse C such that AC = I, and why this is only possible if m≤n.

Uniqueness: Ax = b has at most 1 solution x for every b if and only if the columns are linearly independent. I don't understand why then A has a n x m left inverse B such that BA = I, and why this is only possible if m≥n.

Could anyone explain the logic behind this? Thank you.
 
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Let's start with uniqueness. Suppose A has two columns that are linearly dependent. Can you find x that's not equal to 0 with Ax=0? Hint: it only has two nonzero elements
 
Office_Shredder said:
Let's start with uniqueness. Suppose A has two columns that are linearly dependent. Can you find x that's not equal to 0 with Ax=0? Hint: it only has two nonzero elements
No. A would be a column vector, and only x=0 would work. Why does this lead to the left inverse B such that BA = I, and why it is only possible if m≥n?

Thank you.
 
jolly_math said:
No. A would be a column vector

It's not. You might have misread my question, give it another look :)
 
I'm not sure what the answer is, could you explain the reasoning? Thank you.
 
Can you write out a 2x2 matrix which has two columns that are linearly dependent?
 

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