Existence of unique solutions to a first order ODE on this interval

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SUMMARY

This discussion focuses on proving the existence of unique solutions to a first-order ordinary differential equation (ODE) on the interval (1, ∞). The standard approach involves demonstrating the continuity of the function f(t, x) and its partial derivative. However, the challenge lies in extending the solution beyond an interval within (1, ∞). The discussion references specific conditions, such as the boundedness of f(t, x) and the continuity class C^1, which are essential for ensuring that solutions are defined on the entire interval [0, ∞).

PREREQUISITES
  • Understanding of first-order ordinary differential equations (ODEs)
  • Familiarity with continuity and differentiability concepts in real analysis
  • Knowledge of initial value problems (IVPs)
  • Proficiency in mathematical notation and limits
NEXT STEPS
  • Study the existence and uniqueness theorems for ODEs, particularly the Picard-Lindelöf theorem
  • Explore the implications of the continuity class C^1 on the behavior of solutions
  • Investigate the conditions under which solutions to ODEs can be extended beyond their initial intervals
  • Learn about the role of boundedness in the context of differential equations
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Mathematicians, students studying differential equations, and researchers interested in the theoretical aspects of ODEs and their solutions.

thidmir
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TL;DR
I am trying to find if there is a way to prove the existence and uniqueness of a solution
to a first order ODE on an interval including infinity.
I am trying to find a way to prove that a certain first order ode has a unique
solution on the interval (1,infinity). Usually the way to do this is to show that
if x' = f(t,x) (derivative with respect to t), then f(t,x) and the partial derivative with respect to f are continuous.
However, this would show that a solution exists only on an interval inside (1,infinity).
Is there any way to show that a solution exists on the entire interval?
 
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In general a solution is not obliged to be defined for all ##t\ge 0##. For example $$\dot x=x^2,\quad x(0)=1$$
If in equation ##\dot x=f(t,x)## the function ##f## is such that $$|f(t,x)|\le c_1+c_2|x|,\quad (t,x)\in\mathbb{R}_+\times\mathbb{R}^m$$ then all the solutions to such a system are defined in ##[0,\infty)##. There are a lot of other different sufficient conditions for that
 
The following theorem is also useful.
Assume that $$f(t,x)\in C^1((t_1,t_2)\times D,\mathbb{R}^m)$$ where ##D\subset\mathbb{R}^m## is an open domain.

Assume also that $$|f(t,x)|\le c$$ for all ##(t,x)\in (t_1,t_2)\times D##.

Theorem. Let ##x(t)## be a solution to the following IVP
$$\dot x=f(t,x),\quad x(t_0)=x_0\in D,\quad t_0\in(t_1,t_2).$$ Assume that ##x(t)## is defined in ##[t_0,t^*),\quad t^*<t_2 ## and can not be extended longer than ##t^*##. Then the following limit exists
$$\lim_{t\to t^*-}x(t)=x^*$$ and $$x^*\notin D.$$
 
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