Exoergic Nuclear Reaction: Calculating Mass-to-Energy Conversion Percentage

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SUMMARY

The discussion focuses on calculating the percentage of mass converted into energy in the exoergic nuclear reaction 12D + 13T → 01n + 24He. The participant calculated the initial mass as 5.03u and the final mass as 5.011u, leading to a mass conversion percentage of 99.6%. However, it was clarified that this percentage reflects the mass not converted into energy, indicating a misunderstanding in the interpretation of the results. The correct approach involves using the mass defect and Einstein's equation to determine the energy released.

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  • Understanding of nuclear reactions and terminology, specifically exoergic reactions.
  • Familiarity with mass-energy equivalence, particularly Einstein's equation E=mc².
  • Knowledge of atomic mass units (u) and their conversion to energy (MeV).
  • Ability to perform basic arithmetic operations involving mass calculations.
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  • Explore the implications of exoergic and endoergic reactions in nuclear chemistry.
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Homework Statement



In the following exoergic nuclear reaction,

12D + 13T &rarr 01n + 24He

what percentage of the initial mass is converted into energy?



Homework Equations



(mA +ma)- (mB-mB) =delta m

delta m * u(MeV) = E



The Attempt at a Solution



I'm not sure how to do sub and super scripts but 12D would be deuterium. Anyway I calculted the masses and got (mA+ma)5.03u for the first and (mB+Mb)5.011 for the second. To get the % of the mass converted to energy I divided mb+mB/mA+mA and got 99.6%. A I doing it correctly...(even if I calculated the masses incorrectly)
 
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The number you got, 99.6% (assuming the masses and the arithmetic are right), is the percentage of the original mass *not* converted to energy.
 

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