Expanding Wavefunction in Infinite Well: Fourier Analysis

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SUMMARY

The discussion centers on expanding the wavefunction of a particle in an infinite potential well using Fourier analysis. The initial wavefunction is defined as ψ(x) = u_1^+(x;a) = cos(πx/2a)/√a for |x| < a. To find the wavefunction after the box is expanded to [-b, b], the Fourier coefficient a^{+}_n is calculated using the integral a^{+}_n = 1/b ∫_{-b}^{b} cos(πx/2a)/√a · cos(πx/2b)/√b dx. The discussion confirms that this method is correct and emphasizes the importance of incorporating time dependence in the final wavefunction.

PREREQUISITES
  • Understanding of quantum mechanics, specifically wavefunctions and potential wells
  • Familiarity with Fourier analysis techniques
  • Knowledge of the mathematical properties of cosine functions
  • Basic grasp of time-dependent Schrödinger equation
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I have an infinite well from -a to with a particle in its ground. The initial wavefunction is then

\psi(x) = u_1^+(x;a) = cos(\pi x/ 2a)/\sqrt{a} for |x| < a.

In order to get the wavefunction for this particle when box that is instantaneously expanded to [-b,b] should I apply Fourier analysis via

a^{+}_n = 1/b \int_{-b}^{b}cos(\pi x/ 2a)/\sqrt{a}\cdot cos(\pi x/ 2b)/\sqrt{b}dx

where a^{+}_n is the coefficient of the even wavefunction with that n in the expanded box?
 
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Yes, then put in the time dependence.
 

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