We should probably start a new thread. IMO, this one has outlived its usefulness.
CutterMcCool said:
@marcus & Cepheid,
What I can't seem to find is an accurate number on the measured rate of expansion of the universe.
I attempted to derive the rate of expansion of the observable universe in my previous post (
https://www.physicsforums.com/showpost.php?p=3274439&postcount=34"). I'm talking about the quantity that I called \dot{r}_H, which is the first derivative of the radius of the observable universe (so, basically, its the velocity of the boundary -- I've switched to the common notation of using an overdot to represent differentation with respect to time). I *think* that this expression is correct. I'll have more on how you can actually apply it to compute a numerical answer below.
CutterMcCool said:
There's 70km per second per megaparsec (which I take to be close to the Hubble Constant?)
Yes, this is the Hubble Constant, H
0. I think the current best-determined value of it is ~72 km/s/Mpc.
CutterMcCool said:
which is (oddly) given in one-dimensional terms rather than volume.
Well, there's a spherical symmetry there. It doesn't matter in what direction you're looking, as long as an object is x Mpc away, then it will appear to be receding from you with a velocity of v = H
0x km/s.
CutterMcCool said:
But this number doesn't seem to include the accelerating rate of expansion detected in the late 90's by Perlmutter et al.
The parameter that tells you the ratio of distance to recessional velocity is the Hubble parameter, H. This parameter
changes with time. The Hubble Constant, H
0, is just the value of H
today.
In some sense, H expresses the history of the rate of the expansion of the universe, since H = \dot{a}/a. In this expression, a is the scale factor, and \dot{a} is its derivative (the rate at which it changes with time). The value of the scale factor at time t is basically the ratio of the separation of any two objects at time t to their separation now. So a is 1 today, and a < 1 in the past.
CutterMcCool said:
That number (70km/s/megaparsec) seems equivalent to a 2.27 x 10^-16% increase in volume per second.
I'm not sure how you computed this, and I would ask,
which volume are you considering? H
0 is not a velocity, it's the ratio of velocity to distance. So, the farther out you look, the faster things are moving away (the essence of Hubble's law). That leads me nicely back to my specific example where the volume being considered is the volume of the observable universe. The expression I derived for the velocity was:
\dot{r}_H = \dot{a}x_H + c
How do you actually compute this? Well, plugging in the values that apply today, remembering that H = \dot{a}/a, and that a = 1 today, and that H
0 is the value of H today, we just end up with \dot{a} = H_0 (today). The quantity x
H is the co-moving horizon radius, which is just equal to the physical radius of the observable universe today (about 46 billion light years).
EDIT: I get about a billion m/s, which does mean a fractional increase in radius in 1 second of only about 3e-18. So maybe you weren't too far off.