Expectation of an Hermitian operator is real.

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SUMMARY

The expectation value of an Hermitian operator, denoted as \(\langle \hat{A} \rangle\), is confirmed to be real, as demonstrated through the integral representation involving wave functions \(\phi_l\) and \(\phi_m\). The proof utilizes the property of Hermitian operators where \(\langle \hat{A} \rangle^\ast\) equals \(\langle \hat{A} \rangle\), leading to the conclusion that \(\int \phi_l^\ast \hat{A} \phi_m dx\) is equal to its complex conjugate. This establishes that the expectation value is indeed real, reinforcing the fundamental characteristics of Hermitian operators in quantum mechanics.

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  • Understanding of Hermitian operators in quantum mechanics
  • Familiarity with wave functions and their properties
  • Knowledge of complex conjugates and integrals in mathematical physics
  • Basic principles of quantum mechanics and expectation values
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Students of quantum mechanics, physicists working with Hermitian operators, and anyone interested in the mathematical foundations of quantum theory will benefit from this discussion.

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Homework Statement



WTS \langle \hat{A} \rangle = \langle \hat{A} \rangle^\ast

The Attempt at a Solution



\langle \hat{A} \rangle^\ast = \left(\int \phi_l^\ast \hat{A} \phi_m dx\right)^\ast=\left(\int (\hat{A}\phi_l)^\ast \phi_m dx\right)^\ast= \int \phi_m^\ast \hat{A}\phi_l dx. So far, I haven't seen why this equals \int \phi_l^\ast \hat{A} \phi_m dx.

Thanks
 
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use same fields to show
eg. (\Psi, A\Psi) = (\Psi, A\Psi)^*
 

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