Expected value of variance of Hamiltonian in coherent states

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Homework Help Overview

The discussion revolves around finding the expected value of the variance of energy in coherent states, specifically focusing on the calculations involving non-hermitian and non-commutative lowering and raising operators.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the expected value of the variance, questioning the correctness of their approach and the handling of non-commuting operators. There is a request for clarification on a specific calculation step involving the reduction of an expression related to the operators.

Discussion Status

Some participants have provided feedback on specific steps, indicating that certain calculations appear correct. However, there remains a focus on clarifying the proper method for handling the operators involved, with no explicit consensus reached on the overall approach.

Contextual Notes

Participants are navigating the complexities of operator algebra in quantum mechanics, particularly regarding the properties of coherent states and the implications of non-commutativity.

graviton_10
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Homework Statement
Find the variance of the energy in coherent state |ɑ>.
Relevant Equations
<ΔH> = <ɑ| HH |ɑ>
I am trying to find the expected value of the variance of energy in coherent states. But since the lowering and raising operators are non-hermitian and non-commutative, I am not sure if I am doing it right. I'm pretty sure my <H>2 calculation is right, but I'm not sure about <H2> calculation.

Here is my solution:
 

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Check the step circled in orange. ##a^\dagger## and ##a## don't commute.
 
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Yes, but how to do it the right way?
 
graviton_10 said:
Yes, but how to do it the right way?
Please post the steps for how you reduced ##\langle \alpha | (a^{\dagger} a)^2|\alpha \rangle## to ##|\alpha^*\alpha|^2 \langle \alpha | \alpha \rangle##. That way, we can help you see where you made a mistake.
 
So, I used the fact that the commutator of a and a dagger is 1. Does it look good now?
 

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That looks good.
 

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