Experiment involving surface tension for water and alcohol

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SUMMARY

This discussion centers on measuring the surface tension of a mixture of water and alcohol. The measured surface tension of the mixture is ##\gamma_m = 37 \frac{dyne}{cm}##, while the known surface tensions for pure alcohol and pure water are ##\gamma_a = 22 \frac{dyne}{cm}## and ##\gamma_w = 72 \frac{dyne}{cm}##, respectively. The challenge presented is determining the percentage composition of alcohol and water in the mixture based on these values. Relevant equations include ##\gamma = \frac{F}{L}##, which relates force to surface tension.

PREREQUISITES
  • Understanding of surface tension and its measurement
  • Familiarity with the concept of mixtures in physical chemistry
  • Knowledge of relevant equations, specifically ##\gamma = \frac{F}{L}##
  • Basic algebra for solving equations related to mixture composition
NEXT STEPS
  • Research methods for calculating the composition of binary mixtures using surface tension data
  • Explore the principles of surface tension measurement techniques
  • Study the effects of temperature on the surface tension of liquids
  • Learn about the application of diffraction patterns in measuring surface tension
USEFUL FOR

Students and researchers in chemistry, particularly those focusing on physical chemistry and fluid dynamics, will benefit from this discussion. It is also relevant for anyone conducting experiments involving surface tension measurements of liquid mixtures.

sagigever
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Homework Statement
Lets assume I am doing an experiment of measuring surface tension, I have some

alcohol liquid and I measure ##\gamma_m = 37 \frac{dyne}{cm}## but I know that the surface tension of pure alchohol is ##\gamma_a = 22 \frac{dyne}{cm}## and on the other hand surface tension of pure water is ##\gamma_w = 72 \frac{dyne}{cm}## so it easy to conclude that I have mixture of water and alchohol, now I am asking how can I know the percent of alchohol and water in the mixture

Relevant Equations::
Relevant Equations
##\gamma= \frac{F}{L}##
I really have no idea how to approach this question, I was thinking write ##F=mg## but I am not sure if I can write that even though
 
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sagigever said:
Homework Statement:: Let's assume I am doing an experiment of measuring surface tension, I have some
alcohol liquid and I measure ##\gamma_m = 37 \frac{dyne}{cm}## but I know that the surface tension of pure alchohol is ##\gamma_a = 22 \frac{dyne}{cm}## and on the other hand surface tension of pure water is ##\gamma_w = 72 \frac{dyne}{cm}## so it easy to conclude that I have mixture of water and alchohol, now I am asking how can I know the percent of alchohol and water in the mixture
Relevant Equations:: ##\gamma= \frac{F}{L}##

I really have no idea how to approach this question, I was thinking write ##F=mg## but I am not sure if I can write that even though
This might help: https://arxiv.org/pdf/1802.01648.pdf
Or maybe: https://www.imedpub.com/articles/me...he-diffraction-pattern-of-surface-ripples.pdf
 
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sagigever said:
Homework Statement:: Let's assume I am doing an experiment of measuring surface tension, I have some

alcohol liquid and I measure ##\gamma_m = 37 \frac{dyne}{cm}## but I know that the surface tension of pure alchohol is ##\gamma_a = 22 \frac{dyne}{cm}## and on the other hand surface tension of pure water is ##\gamma_w = 72 \frac{dyne}{cm}## so it easy to conclude that I have mixture of water and alchohol, now I am asking how can I know the percent of alchohol and water in the mixture

Relevant Equations::
Relevant Equations:: ##\gamma= \frac{F}{L}##

I really have no idea how to approach this question, I was thinking write ##F=mg## but I am not sure if I can write that even though
The OP has tried to delete their post after receiving good help. The OP has been restored and the thread is now locked. Please do not try to delete your homework threads after receiving help.
 
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