Expert Tips for Choosing the Perfect Motor - Maximize Your Design's Performance

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SUMMARY

The discussion focuses on selecting an appropriate motor for a design requiring 1.2 A and 12VDC to move a load of 0.5 lbs at 500 rpm. The user initially calculated the required horsepower as 0.5 using torque equations but later realized the correct required horsepower is approximately 0.0476, equating to about 35.5 watts. It was highlighted that the input power of 14.4 watts from the power supply is insufficient, necessitating a larger power supply. Additionally, the importance of accounting for losses such as friction and air resistance when determining power requirements was emphasized.

PREREQUISITES
  • Understanding of basic physics concepts such as force, mass, and acceleration (F=ma).
  • Familiarity with torque calculations (T=Fr).
  • Knowledge of horsepower and power conversion (HP= (T*omega)/5252).
  • Basic electrical principles, including voltage and current calculations (P=IV).
NEXT STEPS
  • Research motor specifications to find options that meet or exceed 35.5 watts for your application.
  • Learn about power supply requirements for motors, focusing on current ratings and voltage compatibility.
  • Investigate methods to calculate and minimize friction and air resistance in motor applications.
  • Explore different types of motors suitable for high torque applications, such as stepper or brushless motors.
USEFUL FOR

Engineers, designers, and hobbyists involved in mechanical design and motor selection, particularly those optimizing performance for specific load and speed requirements.

Kristafer
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Hello, I am working on a design, and I am having trouble selecting a motor. I will be able to supply 1.2 A and 12VDC, and I need the motor to be able to move a load of 0.5 lbs at 500 rpm. So far, I tried calculating torque (based on F=ma and T=Fr, r=1.06 in in this case). Then I used HP= (T*omega)/5252 to get a required Horsepower of 0.5. But I feel like this is wrong. Any advice would be greatly appreciated!
 
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Move a load of 0.5 lbs at what speed, or should that be a load torque of 0.5 ft lbs at 500 rpm == 0.047601 horsepower ~= 35.5 watts. Input power is 1.2A x 12 V = 14.4 watts, so you'll need a bigger power supply.
 
Kristafer said:
I will be able to supply 1.2 A and 12VDC, and I need the motor to be able to move a load of 0.5 lbs at 500 rpm.

As rcgldr said.. There is an issue with your units.

It takes power to accelerate a flywheel but the only power required to spin a 0.5lbs flywheel at a constant 500rpm is the power required to overcome losses (such as friction and/or air resistance).
 

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