Explain Apparent Weight & Fluid Mechanics (3)

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SUMMARY

The discussion centers on the concept of apparent weight in fluid mechanics, specifically regarding a ceramic statue suspended in water. The spring scale initially reads 28.4N when the statue is in air and 17.0N when submerged, indicating that the apparent weight is indeed 17.0N due to buoyancy. The confusion arises from the definition of apparent weight, which is often equated with normal force, yet in this context, it is represented by tension in the spring scale. The tension reflects the reduced force needed to keep the statue at rest in the fluid, demonstrating that apparent weight can manifest in various forms depending on the forces acting on an object.

PREREQUISITES
  • Understanding of Newton's Laws of Motion, particularly Newton's 3rd Law.
  • Basic knowledge of fluid mechanics, including buoyancy principles.
  • Familiarity with the concept of tension in physics.
  • Ability to calculate density using weight and volume measurements.
NEXT STEPS
  • Study the principles of buoyancy and Archimedes' principle in fluid mechanics.
  • Learn about the relationship between tension and apparent weight in different contexts.
  • Explore the concept of normal force and its implications in various physical scenarios.
  • Investigate real-world applications of apparent weight in engineering and design.
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Students of physics, educators explaining fluid mechanics, and professionals in engineering fields who require a deeper understanding of forces acting on submerged objects.

kingwinner
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I don't understand the idea of apparent weight (see example below). Can someone explain? Thanks a lot!

1) You need to determine the density of a ceramic statue. If you suspend it from a spring scale, the scale reads 28.4N. If you then lower the statue into a tub of water, so that it is completely submerged, the scale reads 17.0N. What is the density?
The spring scale's reading is related to the tension T in the spring.
The magniutde of tension T of the statue on the spring scale is equal to the magnitude of tension T of the spring scale on the statute (Newton's 3rd law)
I actually have no problem figuring out the answer for this problem, but there is something that is confusing me! Is the reading of 17.0N the so-called apparent weight of the statute?

I have been told numerous times that apparent weight means the normal force. But in this case the force is TENSION, not normal force, why would it still be called apparent weight? And even more confusing, as far as I know, tension isn't always apparent weight. For example, if you pull a box on the floor horizontally using a rope, that tension force is clearly NOT apparent weight. What is the actual definition of apparent weight? I am very confused...
 
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17N is, indeed the apparent weight, in that some of the ceramic statue's weight is balanced by the buoyancy of the fluid.
Thus, the force that the the spring needs to generate (as tension) in order to keep the statue at rest is less than the statue's actual weight.
 
arildno said:
17N is, indeed the apparent weight, in that some of the ceramic statue's weight is balanced by the buoyancy of the fluid.
Thus, the force that the the spring needs to generate (as tension) in order to keep the statue at rest is less than the statue's actual weight.

But apparent weight means normal force, right? (this is what I have been told for years!) For example, when you are free-falling, your normal force is zero, so your apparent weight is zero.

Then, in this case, why would the tension force also be called apparent weight?

How can I identify whether a particular force is apparent weight or not?
 

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